Answer:
t=14
v=13
q=12
s=23
w=-4
x=28
Step-by-step explanation:
we know that the universal set =100
so, everything in it must add up to 100
first, from the information given to us,
t= n(A n C)= 14
v=n(B n C)= 13
to find q
we know from our guide that n(A) =40
which means everything inside A will add up to 40
therefore,
q + 7 + 7 + t = 40
and we already know that t = 14
so, that will be;
q + 7 + 7 + 14 = 40
therefore, q = 12
to find s,
we all know that n(B) = 50
which means that everything inside B will be equal to 50
therefore,
s + 7 + 7 + v = 50
and we know that v = 13
therefore,
s + 7 + 7 + 13 = 50
and s will end up to be = 23
to find w,
we know that n(C) = 30
so, everything in C end up to be all equal to 30
therefore,
t + 7 + w + v = 30
from our solution, t = 14, v = 13
so,
14 + 7 + w
You don't even have to look up the definition of 'standard deviation'. You only
have to remember that 'smaller standard deviation' means 'less spread-out'.
First, let's find the mean (average). It's not supposed to change:
1/7th of (65 + 71 + 77 + 80 + 82 + 90 + 96) = 561/7 = <u>80 and 1/7</u> .
Now, just pick 7 scores that total 561 and are all bunched up.
The easiest way would be 80, 80, 80, 80, 80, 80, 81 .
But that's so easy that it feels like cheating.
Let's say <u>77, 78, 79, 80, 81, 82, and 84</u> .
Answer:
y = x + 2
If you use y = x, it will become in the direction of that line. I am assuming 1 block = 1 unit of measurement, so y = x + 2.
