Ok so first we find the equation that equals one variable.
2y = -x + 9
3x - 6y = -15
We solve for y.
2y = -x + 9
y = -x/2 + 9/2
Then we plug in this y value into the other equation to keep only one variable so we can solve for it.
3x - 6y = -15
3(-x + 9/2) - 6y = -15
-3x + 27/2 - 6y = -15
-9y + 27/2 = -15
-9y = 3/2
-y = 3/18
y = -3/18
Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.
y = -x/2 + 9/2
-3/18 = -x/2 + 9/2
-84/18 = -x/2
-x = 9 1/3
x = -28/3
Your answer would be (-28/3, -3/18)
Hope this helps!
An integer is close to zero if it is "small".
By small, we mean that it is small in absolute value. In fact, for any given distance 
, there are two integers that are units away from zero: 
and 
.
So, for example, -6 is close to zero than 8, because -6 is six units away from zero, while 8 is eight units away from zero.
So, the answer is B, -8, because it is 8 units away from zero. The other options A, C and D are, respectively, 12, 10 and 14 units away from zero.
Answer:
The answer is 4
Step-by-step explanation:
x^2-2x-8=1/4x-1
x^2-9x/4-7=0
4x^2-9x=28
Therefore if we take value of x as 4 aur eq.get balanced...
