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4 years ago

Solve for y. −140=18+4(5y−2)

Mathematics

2 answers:

OLga [1]4 years ago

4 0

Answer:

the answer is -7.5

vagabundo [1.1K]4 years ago

3 0

For this case we have the following equation:

$-140 = 18 + 4 (5y-2)$

From here, we must clear the value of y.

For this, we follow the following steps:

1) Distributive property:

$-140 = 18 + 20y-8$

2) Variable terms on one side of the equation and constant terms on the other side of the equation:

$20y = -140 - 18 + 8$

3) Algebraically add the constant terms:

$20y = -150$

4) Pass the number 20 to divide:

$y = -\frac{150}{20}\\y = -7.5$

Answer:

The value of y is given by:

$y = -7.5$

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If you can buy one can of pineapple chucks for $2 then how many can you buy with $10?

Elina [12.6K]

Answer:

Step-by-step explanation:

Because two times 5 equals ten

8 0

3 years ago

Read 2 more answers

UCF believes that the average time someone spends in the gym is 56 minutes. The university statistician takes a random sample of

11111nata11111 [884]

Answer:

We conclude that the average time someone spends in the gym is different from 56 minutes.

Step-by-step explanation:

We are given that UCF believes that the average time someone spends in the gym is 56 minutes.

The university statistician takes a random sample of 32 gym goers and finds the average time of the sample was 50 minutes. Assume it is known the standard deviation of time all people spend in the gym is 8 minutes.

Let $\mu$ = population average time someone spends in the gym

SO, Null Hypothesis, $H_0$ : $\mu$ = 56 minutes {means that the average time someone spends in the gym is 56 minutes}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 56 minutes {means that the average time someone spends in the gym is different from 56 minutes}

The test statistics that will be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average time someone takes in the gym = 50 min

$\sigma$ = population standard deviation = 8 minutes

n = sample of gym goers = 32

So, test statistics = $\frac{50-56}{\frac{8}{\sqrt{32} } }$

= -4.243

Since in the question we are not given the level of significance so we assume it to b 5%. Now at 5% significance level, the z table gives critical value between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lie within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the average time someone spends in the gym is different from 56 minutes.

4 0

3 years ago

In circle V, r=14. What is the area of circle V

olasank [31]

Answer:
$\pi$ $14^{2}$ or $\pi 196\\$

Step-by-step explanation:

The circle V has the radius of 14 (r=14)
The formula of area is (A= $\pi r^{2}$ )

So we insert the value of (r=14)
$A=\pi 14^2$
$A=\pi 196$
And that's the answer, The exact value is 615.752...