<span>2(3y - 7) - 5y(2 - y)
2*3y - 2*7 - 5y*2 -5y*(-y)
6y - 14 - 10y + 5y</span>²
5y² + 6y - 10y - 14
<span>5y² -4y - 14</span>
Answer:
Part 1) 
Part 2) The length of the hypotenuse is 6 units
Step-by-step explanation:
Part 1) we know that
In the right triangle of the figure
----> by SOH (opposite side divided by the hypotenuse)
solve for y
Remember that
substitute
Part 2)
Let
h ----> the length of the hypotenuse
we know that
In the right triangle of the figure
----> by SOH (opposite side divided by the hypotenuse)
Remember that
substitute
Answer:
Expert? Sorry, not me, but what sort of questions do you have?
Step-by-step explanation:
Answer
Q1. -8+3
solution:
= -8+3
= -5 .Ans
Rule : if the sign are different subtract and and keep the sign of larger value.
Q2. 7-(-14)
solution :
= 7-(-14)
= 7 + 14
= 21 .Ans
Rule: if the signs are same add and keep the sign same
Q3. 8× (-2)
solution:
= 8×-2
= -16. Ans
(solve bracket first)
Q4. (-39) ÷ (9)
solution:
= -39 ÷ 9
= -4 .Ans
Q5. 24 ÷ 8 × (7+3) ÷ 5
solution:
= 24 ÷ 8 × (10) ÷ 5
= 24÷ 8 × 10 ÷ 5
= 3 × 2
= 6
(Note : According to BODMAS rule, the brackets have to be solved first followed by powers or roots (i.e. of), then Division, Multiplication, Addition, and at the end Subtraction. )
Q6. 8 (2x+9) - 2
solution:
= 8 (2x+9) -2
= 16x + 72 - 2
= 16x + 70 .Ans
Q7. 36y - 8y + 15 - 13
solution:
= 36y- 8y + 15 - 13
= 30y + 2 .Ans
Q8. 3÷ 4
solution :
= 3÷ 4
= 0.75 .Ans
Q9. 8/0
soution: It is undefined or you cannot evaluate it. Explanation: You cannot evaluate 8 /0 because there is no real number.
Q10. 18 /1
solution:
= 18/1
= 18 ÷ 1
= 18. Ans
Explanation :This rule tells us simply that if we have a number divided by 1, our answer will equal that number regardless of what that number is. We don't even have to pay that much attention to the number we are dividing. We just have to make sure that when dividing any number by 1, we remember the answer is always itself.
Q11. 1 ÷ 9-3
solution:
= 1 ÷ 9-3
= 0.1111 - 3
= −2.8888 .Ans
(Note : According to BODMAS rule, the brackets have to be solved first followed by powers or roots (i.e. of), then Division, Multiplication, Addition, and at the end Subtraction. )
