Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
Step-by-step explanation:
Equations
7x + 3y = 4z
<em>Second equation</em>
x + y = z Multiply the entire equation by 4
4[x + y = z] Now distribute the 4 through the equation
4x + 4y = 4z Both equations = 4z. Equate the lefts.
<em>Third equation </em>
7x+3y = 4x + 4y Subtract 3y from both sides
7x + 3y -3y = 4x + 4y -3y
7x = y + 4x Subtract 4x from both sides
7x - 4x = y + 4x - 4x Combine
3x = y
Answer: 3x = y
The distributive property "distributes" a number through all numbers/terms in a set of parentheses by multiplication.
EXAMPLES
Equivalent expressions are the first and last steps. The middle step just shows the work.
5(2 + 3x)= (5*2) + (5*3x)= 7 + 15x
4(2x + 4y)= (4*2x) + (4*4y)= 8x + 16y
10(4x + 5)= (10*4x) + (10*5)= 40x + 50
ANSWER:
Only one pair below is needed for your answer.
5(2 + 3x)= 7 + 15x
4(2x + 4y)= 8x + 16y
10(4x + 5)= 40x + 50
Hope this helps! :)
Answer:
fish
Step-by-step explanation:
Answer:
not enough information sorry
Step-by-step explanation:
