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2 years ago

Look at the number line below.

Mathematics

2 answers:

VikaD [51]2 years ago

5 0

Answer: Choice C)

We start at 0 and move 1.4 units to the right. Then we move another 2.3 units to the right to land on 3.7

Notice how 1.4 - (-2.3) = 1.4 + 2.3 = 3.7

Paraphin [41]2 years ago

3 0

Answer:

Step-by-step explanation:

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A map shows the distance between the corner of cactus road and 1st street and the corner of 1 St Street and Merle road as 3 inch

melamori03 [73]

11.1 miles

1in / 3.7 m = 3 in / 11.1 m

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3 years ago

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I need this whole page solved please

Nuetrik [128]

Answer:

5. 540°

Step-by-step explanation:

m<a + m<c = 180°

m<h + m<f = 180°

m<k + m<m = 180°

Then m<a + m<c + m<h + m<f + m<k + m<m = 180° x 3 = 540°

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1 year ago

Which transformation was performed on PQRS to form P'QʻR'S'? (1 point)

REY [17]

Given:

A transformation was performed on PQRS to form P'QʻR'S'.

To find:

The transformation.

Solution:

The given graph shows two similar polygons. It means, dilation was performed.

From the given graph it is clear that,

$PS=2$ units

$P'S'=1$ units

Now,

$\text{Scale factor}=\dfrac{P'S'}{PS}$

$\text{Scale factor}=\dfrac{1}{2}$

A dilation factor of $\dfrac{1}{2}$ was performed on PQRS to form P'QʻR'S'.

Therefore, the correct option is (3).

3 0

2 years ago

To find the equation of a line, we need the slope of the line and a point on the line. Since we are requested to find the equati

murzikaleks [220]

Answer:

$x-4y+4=0$

$f(x)=\sqrt x$ and x=4

Step-by-step explanation:

We are given that a curve

$y=\sqrt x$

We have to find the equation of tangent at point (4,2) on the given curve.

Let y=f(x)

Differentiate w.r.t x

$f'(x)=\frac{dy}{dx}=\frac{1}{2\sqrt x}$

By using the formula $\frac{d(\sqrt x)}{dx}=\frac{1}{2\sqrt x}$

Substitute x=4

Slope of tangent

$m=f'(x)=\frac{1}{2\sqrt 4}=\frac{1}{2\times 2}=\frac{1}{4}$

In given question

$m=\lim_{x\rightarrow a}\frac{f(x)-f(a)}{x-a}$

$\frac{1}{4}=\lim_{x\rightarrow 4}\frac{f(x)-f(4)}{x-4}$

By comparing we get a=4

Point-slope form

$y-y_1=m(x-x_1)$

Using the formula

The equation of tangent at point (4,2)

$y-2=\frac{1}{4}(x-4)$

$4y-8=x-4$

$x-4y-4+8=0$

$x-4y+4=0$

8 0

3 years ago

A circle with radius \pink{9}9start color #ff00af, 9, end color #ff00af has a sector with a central angle of \purple{120^\circ}1

GrogVix [38]

Answer:

Area of sector = 84.861

Step-by-step explanation:

Given

The radius of the circle = 9

central angle of sector = $120^{o}$

value of pi π = 3.143

To find : the area of sector = ?

We know that the formula to calculate area of sector is given as:

area of sector = (π $r^{2}$ Θ)/ $360^{o}$

where, r is radius and Θ is the central angle of the sector

Substituting the known values in above formula, we get

area of sector = (3.143 x $9^{2}$ x $120^{o}$ ) / $360^{o}$

= 84.861

Hence area of sector is 84.861

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3 years ago

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