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lesya692 [45]
3 years ago
8

I need answers to all of these. Please help!! I suck at math..

Mathematics
1 answer:
RSB [31]3 years ago
6 0
1)  (-4) + (-9) = -13 

2) 5 + (-12) = -7 

3) -6 + 5 = -1 

4) -7 + 7 = 0 

<span>5)  -7 + 2 ___ 3 + (-9)

       - 5  ____    - 6 

</span>-7 + 2  >  3 + (-9)

6)  <span>4 + (-8) ___ 6 + (-8) + (-6)  

     - 4 ____    - 8 

</span><span>4 + (-8) >  6 + (-8) + (-6)

7)  </span><span>$66

8)  </span><span>-$12
</span>
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(6,3*10^-2)÷(2,1*10^4​
nexus9112 [7]

Answer:

  • 3*10^{-6} or 0.000003

Given expression:

  • (6.3*10^{-2}) : (2.1*10^4)

Simplify it in steps below:

  • (6.3*10^{-2}) : (2.1*10^4) =
  • (6.3 :2.1)*(10^{-2}:10^4)=
  • 3*(10^{-2-4})=
  • 3*10^{-6} or 0.000003

<u>Used properties:</u>

\cfrac{ab}{cd}=\cfrac{a}{c}*\cfrac{b}{d}

a^b:a^c=a^{b-c}

a^{-b}=1/a^b

7 0
1 year ago
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The length of Suez Canal on a map of drawing scale 1 : 1400000 is 70 Km ,then its
lapo4ka [179]

Answer:

76

Step-by-step explanation:because its the answer

7 0
2 years ago
Can someone please help I’m not so good at fractions
satela [25.4K]

Answer:

A) 25/33

B) 36

C) 1/15

d) 2 11/12

E) 1 7/12

7 0
2 years ago
Read 2 more answers
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
2 years ago
Need help po, needed today. Thanks! ​
Dimas [21]

Answer:

<h2>question is not up down this is incorrect questions</h2>
8 0
2 years ago
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