The question asks which x-value gives the same y-value for both equations, so if you need the ys to be equal, you can set both equations equal to each other, giving you 6x-16=3x-10. Now, solve for x. 6x-16=3x-10, subtract 3x and add 16, 3x=6, divide 3, x=2. Your answer is x=2.
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
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Ummm this has to be in your textbook
