The density of a population of living organisms is usually measured in individuals on one square km. In here we have 50 earthworms on an area of 5 square meters, thus we have 10 earthworms on every square meter. In order to get to the result we need to see first how many square meters there are in one square km. One square km has one thousand meters of length and one thousand meters of width so:
1,000 x 1,000 = 1,000,000 km²
Since we established that we have 10 earthworms on every one square meter, we just need to multiply the number of square meters with the amount of earthworms on every square meter:
1,000,000 x 10 = 10,000,000
So we have a density of 10 million earthworms per square km.
Answer:
First the water which is present in the sea and ocean evaporated due to the radiation of sunlight which changes liquid into vapours. These vapours goes to the atmosphere and forms cloud. These clouds moves to the hilly areas by winds and falls in the form of rainfall and snowfall. The water which is present in these hilly areas starts melting due to increase in temperature and this water flows down the land through streams and again meets the ocean.
Photosynthesis; light dependent and light independent reactions
Answer:
allelic frequency a = 30%
allelic frequency A = 70%
Explanation:
You are studying a population of sparrows in which the phenotype is determined by a single locus. Only two alleles for this locus are known for this population, which are distinguished by the codes 'A' and 'a'. The distribution of phenotypes in the population indicates that 49% of the population is homozygous 'AA', 42% is heterozygous and 9% 'aa' homozygous. How is the allele frequency for 'A' and 'a' determined based on these observations?
According to the case, the allelic frequency for A and a will be searched with the data:
homozygotes AA = 49%
heterozygotes Aa = 42%
homozygous aa = 9%
Frequency of homozygotes 'aa'
(q 2) = 9/100 = 0.09
we can obtain the allelic frequency of a through the following formula:
a (q) = √0.09
The result will be
= 0.3
we change to percentage
= 30%
we have the following formula
p + q = 1
to find the allele frequency A, represented by p
p = 1 - 0.3
we get the following result
p = 0.7
we change to percentage
= 70%