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xenn [34]
3 years ago
9

-1+14x+14p-2x-5p+18 equals what>

Mathematics
1 answer:
jonny [76]3 years ago
6 0
12x+9p+17
All that you need to do is combine like terms
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In a​ lottery, 6 numbers are randomly sampled without replacement from the integers 1 to 50. Their order of selection is not i
nlexa [21]

Answer: 0.444225

Step-by-step explanation:

Given : The total number of tickets = 50

Number of tickets are randomly sampled without replacement  =6

Since the order of selection is not important , so we use combinations.

Total number of ways to select 6 tickets = ^{50}C_6

The number of winning tickets = 6

So, number of tickets that are not winning = 50-6=44

Number of ways of selecting zero winning numbers= ^{44}C_{6}

Now , the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket out of the 50 possible numbers would be \dfrac{^{44}C_{6}}{^{50}C_6}

=\dfrac{\dfrac{44!}{6!(44-6)!}}{\dfrac{50!}{6!(50-6)!}}\\\\\\=\dfrac{\dfrac{44\times43\times42\times41\times40\times39\times38!}{38!}}{\dfrac{50\times49\times48\times47\times46\times45\times44!}{44!}}\\\\\\=\dfrac{44\times43\times42\times41\times40\times39}{50\times49\times48\times47\times46\times45}\\\\=\dfrac{252109}{567525}\approx0.444225

Hence, the required probability = 0.444225

8 0
3 years ago
A tree standing vertically on level ground casts a 140 foot long shadow. The angle of elevation from the end of the shadow to th
fredd [130]
<span>Let the height of the tree be h foot. Trigonometric ratio for tangent = Opposite side / adjacent side----(1) Since the tree is standing vertically on a level ground, the three points, [ Top of the tree, the point where the tree touches the ground and the point where the shadow ends] form a right angled triangle. Applying (1) for the above three points, tan(24.7)=(height of the tree)/(length of shadow) Hence, height of the tree = tan(24.7)*(length of the shadow) = (0.46)*140 = 65 foot (Rounding off to the nearest foot)</span>
3 0
3 years ago
What adds to 10 and multiplies to -300
Anton [14]
X+Y=10
XY=-300

Solve for one of the variables

X=10-Y

Plug into the other equation

Y(10-Y)=-300

Now, you have a quadratic...

-y²-10y+300=0

I would multiply everything by -1, so there's no coefficient on y²

y²+10y-300=0

And solve...

-10±√(100-4(-300))
----------------------------
2

Y=-5±5√(13)

Plug back onto original equation...

X+(-5±5√(13))=10
X±5√(13)=15
X=15±5√(13)

Note: There are 2 sets of answers, keep the negatives with the negatives, and the positives with the positives when dealing with the ±.
8 0
4 years ago
Which is the following sum? 4√5+2√5 6√10 8√10
Kruka [31]

Answer:

the answer is 6 square root 5

Step-by-step explanation: ANSWER IS C

5 0
3 years ago
Solve.<br><br> 10x + 16 &gt; 6x + 20
oee [108]
X>1 is the answer
10x + 16 > 6x +20
4x +16 > 20
4x > 4
x > 1
4 0
4 years ago
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