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serious [3.7K]
3 years ago
12

Describe steps to simplify w(5w^3)^-2 / w^-4

Mathematics
1 answer:
Ulleksa [173]3 years ago
3 0
[w*(5w^3)^-2]/(w^-4)

first rules to consider a^(-b)=1/a^b, (a^b)^c=a^(b*c),   (a^b)*(a^c)=a^(b+c)

[w/(5w^3)^2]/(w^-4) 

(w*w^4)/(25w^6)

w^5/(25w^6)

Then you have the quotient rule for powers (a^c)/(a^b)=a^(c-b)

1/(25w)

which we could state as:

(25w)^(-1) :P
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Answer:  " 15 % " .

_______________________________

     →   " 12 is <u>  15% </u> of 80 " .

_______________________________

Step-by-step explanation:

_______________________________

12 = (n/100) * 80 ;

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_______________________________

8n = 120 ;

Divide each side of the equation by "8" ;

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_______________________________

to get:

_______________________________

n = 15 .

_______________________________

Answer:  " 15 % " .

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     →   " 12 is <u>  15% </u> of 80 " .

_______________________________

Hope this helps!

Best wishes!

_______________________________

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