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serious [3.7K]
4 years ago
12

Describe steps to simplify w(5w^3)^-2 / w^-4

Mathematics
1 answer:
Ulleksa [173]4 years ago
3 0
[w*(5w^3)^-2]/(w^-4)

first rules to consider a^(-b)=1/a^b, (a^b)^c=a^(b*c),   (a^b)*(a^c)=a^(b+c)

[w/(5w^3)^2]/(w^-4) 

(w*w^4)/(25w^6)

w^5/(25w^6)

Then you have the quotient rule for powers (a^c)/(a^b)=a^(c-b)

1/(25w)

which we could state as:

(25w)^(-1) :P
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3 (1 2t) = 3t + 5 !!​
Nadya [2.5K]

Answer:

2/3

Step-by-step explanation:

3+6t=3t+5

like terms together

6t-3t=5-3

3t=2

t=2/3

6 0
3 years ago
Five and thirty-nine thousandths in standard decimal form
Nesterboy [21]

Answer:

Five and thirty-nine thousandths in standard decimal form is

5.039

Hope This Helps!!!

7 0
3 years ago
Which is a correct two-column proof?<br> Given: ∠h and ∠c are supplementary.<br> Prove: j || l
erica [24]
Well currently, we don't have sufficient evidence to prove that. we don't even know anything about j and l
6 0
3 years ago
At the bakery where you work, loaves of bread are supposed to weigh 1 pound, with a standard deviation of 0.13 pounds. You belie
saveliy_v [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

H0 : μ = 1

H1 : μ > 1

Sample size, n = 20 ; xbar = 1.05; Standard deviation, s = 0.13

Test statistic;

t because sample size is < 30

(xbar - μ) ÷ (s/sqrt(n))

(1.05 - 1) ÷ (0.13 / sqrt(20))

0.05 ÷ 0.0290688

= 1.7200572

Using a p value calculator :

With alpha = 0.05 ; df = n - 1 = 20 - 1 = 19

P value = 0.05084

P value > alpha

We fail to reject H0

There is not sufficient evidence to support that the new personnel are producing loaves that are heavier than 1 pound

8 0
3 years ago
Can someone helpppppp
coldgirl [10]

Answer:

13.7

Step-by-step explanation:

We know that sin(thetha) = BC/AB

In this case, thetha = 41, BC = 9in

→ AB = BC/sin(thetha)

→ AB = 9in/sin(41)

→ AB = 13.7

Therefore, the result is 13.7

5 0
4 years ago
Read 2 more answers
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