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Nat2105 [25]
3 years ago
7

A rectangular flower bed that is 5 ft long and 4 feet wide is surrounded by a square lawn that is

Mathematics
1 answer:
mr Goodwill [35]3 years ago
6 0

Answer:

124 ft2

Step-by-step explanation:

The yard is a 12ft square so the length and width would both be 12ft. You multiply the length and width of the yard to get the area of the yard so 12x12=144. You have the length and width of the flower bed so 5x4=20. Once you have the area of both you can subtract the area the flower bed takes up of the lawn. 144-20=124 ft2.

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Solve for x.<br><br> −(−2−5x)+(−2)=18<br><br> x=−90<br> x=90<br> x=185<br> x=−185
Tomtit [17]
Uhm, did you, maybe, type in the problem wrong? The answer to this equation is: 18/5 or 3.6, lol, no worries, though!
5 0
3 years ago
Read 2 more answers
Super legend this is still a hard question but im trying to get rid of my points i like to stay at the bottom of the point list,
Alla [95]
$3 went to the men and and $2 to the bellboy. That's $5 in total, which is what the bellboy was supposed to give the men. So the $1 is with one of the men.
7 0
3 years ago
What is the following quotient?
almond37 [142]

Answer:

B)  \sqrt{30}  - 3 \sqrt{2}  +  \sqrt{55}  -  \sqrt{33}  \div 2

Step-by-step explanation:

Step 1: First we have to get rid off the roots in the denominator.

To do that, we have to multiply the numerator and the denominator by the conjugate of √5 + √3.

The conjugate of √5 + √3 is √5 - √3.

Now multiply given expression with √5 - √3

(√6 + √11)     (√5 - √3)

------------- x   -----------

(√5 + √3)        (√5 - √3)

Step 2: Multiply the numerators and the denominators.

√6√5 - √6√3 +√11√5 -√11√3

------------------------------------------

(√5)^2 - (√3)^2

Now let's simplify to get the answer.

√30-√18 +√55 - √33

-----------------------------

5 - 3

= √30 -3√2 +√55                                     [√18 = √9√2 = 3√2]

--------------------------

2      

The answer is  \sqrt{30}  - 3 \sqrt{2}  +  \sqrt{55}  -  \sqrt{33}  \div 2


Thank you.

4 0
3 years ago
Read 2 more answers
Write the equation for a rational function with a hole at x = 6 and
Kisachek [45]

Answer:

x-6/x²-x-30

Step-by-step explanation:

(x-6)(x+5)

x²-x-30

when you factor out  x-6 you have a removable discontinuity and you have x+5 as your denominator and that would be the vertical asymptote since you can have a 0 as your denominator the V.A. would be x = -5.

6 0
3 years ago
Given that f(x)=x^2-7x-1, g(x)=2x-3, and h(x)=4x-5 find each function. (f+g)(x)
Alexxandr [17]

Answer:

x^2-7x-1+2x-3

x^2-5x-4

5 0
3 years ago
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