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kodGreya [7K]
3 years ago
8

Not sure how I would do this any buddy can help me

Mathematics
2 answers:
Serga [27]3 years ago
6 0
To check the relationship between the lines is to check their slopes.
The slope of WX is (5-(-3))/(-1-0)= 8/-1 = -8
The slope of YZ is (2-5)/(-1-2)= 1 
The slopes are not equal nor are negative reciprocals of each other. That's why they are neither. 

C. Neither

Hope this helps :)
Alinara [238K]3 years ago
4 0
I beilive the answer to that is niether.


hope this helped!
You might be interested in
The problem is in the picture​
Aleonysh [2.5K]

Answer:

27%

Step-by-step explanation:

In the row Students ages 14-17 and column skip breakfast, there are 24 students.
In row total and column total, there 90 students.

24/90 are students age 14-17 who skip breakfast

24/90 = 12/45 = 0.26666667

Percent = decimal x 100

Percent = 0.26666667 x 100 = 26.666667

26.666667 is rounded to 27%

Hope this helps :)

Have a nice day!

5 0
3 years ago
Read 2 more answers
Sandra bought 30 T-shirts at the clothing store. 20% of the T-shirts were blue and half of the T-shirts were black. How many of
insens350 [35]
So you have 20% of blue and 50% of black.
So you have 70% in total that are both blue and black.
100%- 70%= 30%
So that means 30% were neither blue or black.
Do a proportion
30/100= x/30
30 x 30= 900
900 divided by 100= 9
Answer is 9 shirts are neither blue or black
8 0
3 years ago
Which of the following slopes of a line passes through points (2, 3) and (4,7) ?
serg [7]

Answer:

2

Step-by-step explanation:

slope = (difference in y)/(difference in x)

slope = (7 - 3)/(4 - 2)

slope = 4/2 = 2

Answer: 2

8 0
3 years ago
Find the integral, using techniques from this or the previous chapter.<br> ∫x(8-x)3/2 dx
Soloha48 [4]

Answer:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

Step-by-step explanation:

For this case we need to find the following integral:

\int x(8-x)^{3/2}dx

And for this case we can use the substitution u = 8-x from here we see that du = -dx, and if we solve for x we got x = 8-u, so then we can rewrite the integral like this:

\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)

And if we distribute the exponents we have this:

\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du

Now we can do the integrals one by one:

\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C

And reordering the terms we have"

\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C

And rewriting in terms of x we got:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

And that would be our final answer.

8 0
3 years ago
A team of runners is needed ti run 1/4- mile relay race.if each runner must run 1/16 mile,how many runners will be needed
Pavel [41]

If each runner must run 1/16 of 1/4 mile then you need 4 runners because four runners makes 4/16 points. this number is equivalent to 1/4 which proves this statement true

4 0
3 years ago
Read 2 more answers
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