All categories

2 years ago

Health club a charges 100.00 membership fee plus 25.00 per plus 25.00 per month

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

5 0

Answer:

Month 5 the cost will be the same

Step-by-step explanation:

Make to equations from the given information

Let y be the cost, and let x be the number of months

Club A: y = 25x + 100

Club B: y = 20x + 200

It wants to know when the cost will be the same, so set the 2 equations equal to each other and solve..

25x + 100 = 20x + 200

5x = 100 (subtract 20x and 100 from both sides)

x = 20 (divide both sides by 5)

So after 5 months the cost will be equal,

You might be interested in

Find quotient 10/6 / 1/ 24

Maru [420]

Answer:

Step-by-step explanation:

Quotient means dividing so we must divide 10/6 by 1/24.

10/6 ÷ 1/24

10/6 * 24/1 = 40 <--- Multiply by the reciprocal in order to divide.

Final Answer: 40

I hope this helps! :)

3 0

1 year ago

The sum of 30 times (1-3)^(n-1) from n=1 to infinity

kati45 [8]

I can’t do it rn so just dm me later

7 0

2 years ago

I need hw help can someone help me

Pie

What do you need help on? Just post the question.

6 0

2 years ago

Read 2 more answers

What is the margin of error for a yes/no survey of 200 people with a proportion of 65% who answered \"yes\"?. A. ±3.37%. B. ±5.0

azamat

$\sqrt{(p*q)/n}$

where p is the number of positive outcomes (yes) and q is the number of negative outcomes (no).

$\sqrt{(0.65*(1-0.65))/200}$ = 0.0337 or 3.37%

answer is A.

6 0

3 years ago

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

2 years ago