Y=2/3 times x/1-3
=y=2x/3-3
y=2/3x-3
According to google A. Would be 2.375 or as a fraction it would be 2 3/8
In order to answer this we need the table, however to do this all you would do would be to multiply the p value in the table with the corresponding r value in the table and then multiply this by 5, then order them, smallest to greatest.
Answer:
t = 2.52 seconds
Step-by-step explanation:
h=139-15t-16t^2
We want to know when the ball hits the ground
That would be when h=0
0 = 139-15t-16t^2
We can use the quadratic formula to find t
t = -b ± sqrt(b^2-4ac)
----------------------
2a
where a = -16 b = -15 and c = 139
t = -(-15) ± sqrt((-15)^2-4(-16)139)
----------------------
2(-16)
t = (15) ± sqrt(225+8896)
----------------------
-32
t = (15) ± sqrt(9121)
----------------------
-32
t = 15+ sqrt(9121) t = 15- sqrt(9121)
-------------------- or -------------------
-32 -32
-3.453247707 or 2.515747707
Since time cannot be negative
2.515747707
Round to the nearest hundredth
t = 2.52 seconds
The GCF is only 12 because 16 can't multiply a number that gives you 48 only 12.
