7 is the prime factor of 210
<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
4
x
+
y
−
2
z
=
0
4
x
+
y
-
2
z
=
0
,
2
x
−
3
y
+
3
z
=
9
2
x
-
3
y
+
3
z
=
9
,
−
6
x
−
2
y
+
z
=
0
-
6
x
-
2
y
+
z
=
0
x
+
2
y
=
4
x
+
2
y
=
4
,
2
x
+
4
y
=
8
2
x
+
4
y
=
8
3
x
+
y
=
4
3
x
+
y
=
4
,
6
x
−
7
y
=
2
Answer:
I dont know uhm i think no sorry if im wrong
Step-by-step explanation:
Divide by 2. 10/2 divided by 2 = 5/1