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Mnenie [13.5K]
2 years ago
7

19. The cost function of a product is C(Q) = 3Q² +8 and the demand function of the same product is P =1/3 Q² — 10Q + 105, where

Q is output, P the price per unit output. a) Find the marginal cost when output is 4 b) Find the marginal revenue at the output level 4. c) Find the marginal profit at the output level 4. d) Also find the maximum profit.
​
Mathematics
1 answer:
Kamila [148]2 years ago
3 0

The marginal revenue at the output level 4 is 24, marginal revenue at the output level 4 is 41, and marginal profit at the output level 4 is 17.

<h3>What is a marginal cost?</h3>

It is defined as the cost showing an increase in the cost when the number of units produced increases, In simple words it is the ratio of the cost to quantity.

We have a cost function of a product:

C(Q) = 3Q² +8

a) To find the marginal cost to differentiate it with respect to Q and plug

Q = 4:

C'(Q) = 6Q

C'(4) = 6(4) = 24

b) R(Q) = P×Q

\rm R(Q) = (\dfrac{1}{3} Q^2 - 10Q + 105)Q

\rm R(Q) = \dfrac{1}{3} Q^3 - 10Q^2 + 105Q

R'(Q) = Q² - 20Q + 105

Plug Q = 4

R'(Q) = (4)² - 20(4) + 105

R'(Q) = 41

c) Marginal profit:

MP(Q)  = R(Q) - C(Q)

After calculating:

\rm MP(Q)  = \dfrac{1}{3}Q^3-13Q^2+105Q-8

MP'(Q) = Q² - 26Q + 105

Plug Q = 4

MP'(Q) = 16 - 104 + 105 = 17

Similar, we can find the maximum profit.

Thus, the marginal revenue at the output level 4 is 24, marginal revenue at the output level 4 is 41, and marginal profit at the output level 4 is 17.

Learn more about the marginal cost here:

brainly.com/question/7781429

#SPJ1

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This is one single number slightly over 17 thousand.

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Explanation:

Let's say that another person steps in for Joe, Susan, John, and Meredith. I'll refer to this person as the teacher (perhaps these 9 friends are students on a field trip).

The 9 friends drops to 9-4 = 5 people when those four named people leave the group temporarily. Then it bumps up to 5+1 = 6 people when the teacher steps in. Wherever the teacher is located, the four friends that left will replace the teacher. This guarantees that those four friends stick together.

There are 6! = 6*5*4*3*2*1 = 720 ways to arrange those 6 people. The exclamation mark is a factorial symbol.

Within any of those 720 permutations, we have 4! = 4*3*2*1 = 24 ways to arrange those group of named people when they come back to replace the teacher.

So overall the answer is 4!*6! = 24*720 = 17,280

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Side note: There are 9! = 362,880 ways to arrange all nine friends regardless if those four mentioned people stick together or not. We see that they stick together roughly (17,280)/(362,880) = 0.0476 = 4.76% of the time.

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