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3 years ago

50+24/(6x2) Please solve and show work. Thank you.

1 answer:

6 0

50+246x2

=300x^2+24/6x^2
the answer is =50x^2+4/x^2

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Let’s look at another one of Homer’s rocket launches. It was launched from ground level with an initial velocity of 208 feet per

kozerog [31]

Answer:

Smax = 676 ft

the maximum altitude (height) the rocket will attain during its flight is 676 ft

Step-by-step explanation:

Given;

The height function S(t) of the rocket as;

S(t) = -16t2 + 208t

The maximum altitude Smax, will occur at dS/dt = 0

differentiating S(t);

dS/dt = -32t + 208 = 0

-32t +208 = 0

32t = 208

t = 208/32

t = 6.5 seconds.

The maximum altitude Smax is;

Substituting t = 6.5 s

Smax = -16(6.5)^2 + 208(6.5)

Smax = 676 ft

the maximum altitude (height) the rocket will attain during its flight is 676 ft

8 0

3 years ago

Use a matrix to solve the system:

Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

$2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\$

Rewrite these equations in matrix form

$\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\$

we can write it like this,

$AX=B\\X=A^{-1}B$

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

$A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right] \\$

now multiply the matrix with B

$X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\$

4 0

3 years ago

How much it will take for a bag to travel 5 meters across the floor of it is traveling at 1 m/s

tester [92]

Time = $\frac{distance}{speed}$

The distance the bag will travel is 5 meters, and the speed it is traveling at is 1 m/s. Plug these into the formula for time.

$\frac{5 m}{1 m/s}$ = 5 s
5/1 = 5 and the m (meters) cancel out, so you are left with s, seconds.

It will take the bag 5 seconds to travel across the floor.

5 0

3 years ago

Someone plz help me I will give brainliest

makvit [3.9K]

Answer:

2. 3/4 x 5/9 = 3x5/4x9 = 15/36 = 5/12

4. 4/7 x 1/2 = 4x1/7x2 = 4/14 = 2/7

6. 4/9 x 2/3 = 4x2/9x3=8/27

Step-by-step explanation:

Hope it helps!

5 0

3 years ago

Read 2 more answers

Please help me with this math problem.

NARA [144]

WHERE IS THE MATH PROBLEM

5 0

4 years ago