Let the four consecutive integers be
x , x+1, x+2, x+3
ATQ, Their sum is 18
<h3>Now,</h3>
- 1st number = x = 3
- 2nd number = x+1 = 3+1 = 4
- 3rd number = x+2 = 3+2 = 5
- 4th number = x+3 = 3+3 = 6
<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>
Answer:
Integer 1 is x
Integer 2 is y
x + y = -31
x - y = -55
Add:
2x = -86
x = -43
Substitute:
-43 + y = -31
y = 12
Therefore, the two integers are: 12 and -43
The completion is certainly not unique. Multiplying any of the new vectors by a nonzero constant will not affect the span or the linear independence<span>, but will change the </span>basis<span>. </span>To prove<span> that you can </span>extend<span> any </span>linearly independent set<span> S to a </span>basis<span>, you proceed by an iterative argument. If S spans you are done. hope this helps :)</span>
Answer:
5 bouquets
4 roses 2 tulips 1 daisy
Step-by-step explanation:
Find a number that can be divided in to all the values given, that would be the number of groups or in this case bouquets you have. The number you get after you divide Ex: 20/5 is the amount in each group/bouquet
Probability would be low but could happen depending on how you rol the die. So it could happen but theres a really low chance of it happening.
