Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Answer:
105 cm²
Step-by-step explanation:
The figure is composed of a rectangle and a triangle
area of rectangle = 15 × 6 = 90 cm²
area of triangle = 
bh ( b is the base and h the height )
Here b = 15 - 9 = 6 and h = 11 - 6 = 5 , thus
area of triangle = × 6 × 5 = 3 × 5 = 15 cm²
Total area = 90 + 15 = 105 cm²
<span>If m = 7x + 7, m = 4y, and m = 112
since m = 112
112 = 7x + 7
112 - 7 = 7x
105= 7x
x = 15
112 = 4y
y = 28</span>
The answer would be -18°F at 6AM
Hope this helps ?(:
Answer:
Step-by-step explanation:
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