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vlada-n [284]
3 years ago
11

In foot x-ray, what is the distance/FFD and Why?

Physics
1 answer:
MakcuM [25]3 years ago
5 0

Answer and Explanation:

FFD is the distance between the film on which the image is obtained and the center of the anode tube. The magnification and resolution of the image depends on the FFd By varying the FFD we can change the magnification and resolution of the image. The standard FFD is about 100 centimeters.

New studies have found that by changing the FFD to 130 cm the radiation dosage reduces while the image quality remains practically the same.

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zavuch27 [327]

The answer is invention. Technology is vital to science for purposes of dimension, data gathering, treatment of samples, calculation, transport to research sites, defense from hazardous materials, and communication. So technology is new tools and techniques that are being industrialized that make it conceivable to progress various lines of scientific investigation.

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4 years ago
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a compound is 24.7% calcium, 1.2% hydrogen, 14.8% carbon, and 59.3% oxygen. write the empirical formula and name the compound.
Tema [17]
For simplicity, assume that the total mass of the compound is 100 g.

Therefore, by mass
Ca = 24.7 g, H = 1.2 g, C = 14.8 g, and O = 59.3 g

Converting these to moles

Mol = mass*1/atomic mass
Ca = 24.7*1/40.078 =0.6163 mol Ca
H = 1.2*1/1.01 = 1.1881 mol H
C = 14.8*1/12.01 = 1.2323 mol C
O = 59.3/16 = 3.7062 mol O

Next, divide all the mols by the smallest value obtained.

Ca: 0.6163/0.6163 = 1 mol Ca
H: 1.1881/0.6163 = 2 mol H
C: 1.2323/0.6163 = 2mol C
O: 3.7062/0.6163 = 6 mol O

Therefore, empirical formula of the compound is

CaH2C2O6

This compound is referred to as Calcium Bicarbonate
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