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vlada-n [284]
3 years ago
11

In foot x-ray, what is the distance/FFD and Why?

Physics
1 answer:
MakcuM [25]3 years ago
5 0

Answer and Explanation:

FFD is the distance between the film on which the image is obtained and the center of the anode tube. The magnification and resolution of the image depends on the FFd By varying the FFD we can change the magnification and resolution of the image. The standard FFD is about 100 centimeters.

New studies have found that by changing the FFD to 130 cm the radiation dosage reduces while the image quality remains practically the same.

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A battery with an emf of 12.0 V shows a terminal voltage of 11.8 V when operating in a circuit with two lightbulbs rated at 3.0
Blababa [14]

Answer:

R = 24 ohm

Explanation:

As we know that terminal voltage and EMF of cell is given as

V = EMF - ir

ir = 12 - 11.8

ir = 0.2 Volts

resistance of two bulbs is given as

R = \frac{V^2}{P}

R = \frac{12^2}{3}

R = 48 ohm

now these two bulbs are connected in parallel

so equivalent resistance is given as

\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}

\frac{1}{R} = \frac{1}{48} + \frac{1}{48}

so we have

R = 24 ohm

3 0
3 years ago
A dart is thrown from 1.50 m high at 10.0 m/s toward a target 1.73 m from the ground. At what angle was the dart thrown?
Triss [41]

Answer:

The angle of projection is 12.26⁰.

Explanation:

Given;

initial position of the dart, h₀ = 1.50 m

height above the ground reached by the dart, h₁ = 1.73 m

maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m

velocity of the dart, u = 10 m/s

The maximum height reached by the projectile is calculated as;

H_m = \frac{u^2sin^2 \theta}{2g}

where;

θ is angle of projection

g is acceleration due to gravity = 9.8 m/s²

H_m = \frac{u^2sin^2 \theta}{2g}\\\\sin^2 \theta = \frac{H_m \ \times \ 2g}{u^2} \\\\sin^2 \theta = \frac{0.23 \ \times \ 2(9.8)}{10^2} \\\\sin ^2\theta =0.04508\\\\sin \theta = \sqrt{0.04508} \\\\sin \theta = 0.2123\\\\\theta  = sin^{-1}(0.2123)\\\\\theta  = 12.26^0

Therefore, the angle of projection is 12.26⁰.

6 0
3 years ago
What class lever is a
Alchen [17]

should be 1

Explanation:

because what do you use in class and has a lever

8 0
3 years ago
A car, a bicycle, a bus, and a motorcycle are moving parallel to each other on a road. Each vehicle is traveling at the same spe
Olin [163]
The BUS will have the highest kinetic energy, while the BICYCLE will have the lowest kinetic energy.

This is because if an object has a greater mass, the kinetic energy of the object also increases. Kinetic energy depends on mass and velocity (KE=1/2*m*v^2) and since the velocity of these vehicles are the same, the mass is the only difference
4 0
4 years ago
The moon's illumination changes in a periodic way that can be modeled by a trigonometric function. On the night of a full moon,
kupik [55]

Answer:

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

Explanation:

The expression for the  trigonometric function is :

L(t) = A (cos (B(t - C)))+ D   ----- equation (1)

where ;

A = \frac{max-min}{2}

A = \frac{0.25-0}{2}

A = 0.125

D = \frac{0+.025}{2}

D = 0.125

Period of the lunar cycle = 29.53

Then;

\frac{2 \pi}{B}  = 29.53

29.53 \ \ B = 2 \pi

B = \frac{2 \pi}{29.53}

B = \frac{\pi}{29.53}

Also; we known that December 25 is 7 days before January 1.

Then L(-7) = 0.025

Plugging all the values into trigonometric function ; we have:

0.125 ( cos ( \frac{\pi}{14.765}((-7)-C)))+0.125 = 0.25 \\ \\ \\  ( cos ( \frac{\pi}{14.765}((-7)-C))) = \frac{0.25-0.125}{0.125}

( cos ( \frac{\pi}{14.765}((-7)-C))) = 1

( \frac{\pi}{14.765}((-7)-C))= cos^{-1} (1)

}((-7)-C))=0

C= -7

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t-(-7))) + 0.125

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

7 0
3 years ago
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