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Olegator [25]
3 years ago
14

Given that (6,-8) is on graph f(x), find the corresponding point for the function f(-1/2x)

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
8 0
Set the argument -1/2x equal to the x coordinate of the given point 6. Solve for x

-1/2x = 6
x = 6(-2)
x = -12

So x = -12 makes the equation -1/2x = 6 true. 

If we plug x = -12 into f(-1/2x) we get f(6)

Since we know that (6,-8) is on the graph of f(x), we know that (-12,-8) is on the graph of f(-1/2x)

What happens is that there's a reflection over the y axis (due to the minus sign in -1/2x) and there's a horizontal stretch by a factor of 2. So the graph of f(-1/2x) appears to be wider than f(x).

In summary, the final answer is (-12,-8)
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Here is an addition sentence.
kiruha [24]

Answer: B. 3+(1+11)=15


Step-by-step explanation:

1. By definition, the associative property of addition is:

(a+b)+c=a+(b+c)

2. Therefore, if you have the following expression:

(3+1)+11=15

You apply  the Asociative property of addition by regrouping the numbers as following:

3+(1+11)=15

3. Then, you can conclude that the correct option is B.

4 0
3 years ago
What is the value of x in the figure?
finlep [7]
<h3>Answer:  x = 29</h3>

======================================================

Work Shown:

x+61 = 90

x+61-61 = 90-61

x = 29

------------

Explanation:

  • The first step is valid because the two angles x and 61 are complementary angles. They form a right angle or 90 degree angle.
  • In the second step, I subtracted 61 from both sides to undo the "+61".
3 0
3 years ago
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Convert (2, π) to rectangular form
blagie [28]

Answer: 0 . x=2⋅0.

Hope this helps!

3 0
3 years ago
PLEASE HELP: The mass of a ball is 128 g. It has a density of 0.5 g/cm³. What is the volume of the ball? Show your work and plac
tiny-mole [99]

Answer:

Part 1) The volume of the ball is 256 cm³

Part 2) The radius of the ball is 3.94 cm

Step-by-step explanation:

Part 1) we know that

The density is equal to divide the mass by the volume

D=m/V

Solve for the volume

The volume is equal to divide the mass by the density

V=m/D

In this problem we have

m=128 g

D=0.5 g/cm³

substitute

V=128/0.5=256 cm³

Part 2) what is the radius of the ball?

we know that

The volume of the sphere (ball) is equal to

V=\frac{4}{3}\pi r^{3}

we have

V=256\ cm^{3}

assume

\pi =3.14

substitute and solve for r

256=\frac{4}{3}(3.14)r^{3}

768=(12.56)r^{3}

r^{3}=768/(12.56)

r=3.94\ cm

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3 years ago
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