Answer:
Step-by-step explanation:
1. Move the 6 to the other side: x^2 +4x =6
2. Square half the coefficient of the x term: (4/2)^2 = 4
3. Add this 4, and then subtract this 4, from x^2 + 4x:
x^2 +4x + 4 - 4 =6
4. Rewrite this perfect square as the square of a binomial:
(x + 2)^2 - 4 = 6
5. Add 4 to both sides: (x + 2)^2 = 10
6. Find the sqrt of both sides: x + 2 = √
Hello from MrBillDoesMath!
Answer:
(x+2) ( x^2 + 3)
Discussion:
x^3 + 2x^2 + 3x + 6 =
(
x^3 + 2x^2) + (3x + 6) = => factor "x^2" from the first term; factor 3
from the second term
x^2( x + 2) + 3( x+2) = => factor (x+2) from each term
(x+2) ( x^2 + 3)
Thank you,
MrB
I don't understand the question
I think it’s .22 I’m not sure hope this helps :)
Is 10 and 15 because they both have a value of .909
