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3 years ago

6

The landscaper pours 200 gallons of herbicide in the pond. If the herbicide degrades 10% each week, how much will be in the pond

after 1 week passes?

1 answer:

777dan777 [17]3 years ago

5 0

I belive at 90% will be left

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Find the functional values g (-3), g (0), and g (5) for the compound function.

Zinaida [17]

Answer:

$g(-3)=7$

$g(0)=7$

$g(5)=\dfrac15$

Step-by-step explanation:

$g(x) =\begin{cases}7 & \text{if } x \leq 0 \\ \\\dfrac{1}{x} & \text{if } x > 0\end{cases}$

This means:

when x is equal to zero or less than zero, g(x) will always be 7.

when x is more than zero, g(x) is $\frac{1}{x}$

$\implies g(-3)=7$

$\implies g(0)=7$

$\implies g(5)=\dfrac15$

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1 year ago

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What is 27/125 in exponential form?

stealth61 [152]

3/5 I think is the answer

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2 years ago

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Please help solving this ! Which net represents the figure?

Sergeeva-Olga [200]

Answer:

upper right

Step-by-step explanation:

The net for a figure is a representation of all of the figure's faces. The polygons in the net are joined on an edge corresponding to a common edge between the faces they represent.

The given figure is a rectangular prism. Its faces are only rectangles. All nets that have triangles in the net can be eliminated from consideration.

The appropriate choice is the one attached.

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1 year ago

What is real world meaning

grin007 [14]

The definition of a real-world equation is an equation that could perhaps occur in real life, for things like construction.

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2 years ago

A city that had 7500 thousand people at the beginning of the year 2000 has been decreasing by 3.6% per year. a. What is the 1-ye

storchak [24]

Answer:

Step-by-step explanation:

a) if the population at the beginning of the year 2000 was 7500 people,

The 1-year percent change in the city's population would be

3.6/100 × 7500 = 270

b) The population after 1 year is

7500 - 270 = 7230

The percentage of the previous value of the population to its new value for each year is

7230/7500 × 100 = 96.4%

c) the 1-year growth factor for the population of the city would be

(1 - 0.036)^1 = 0.964

d) the function, g that determines the population of the city (in thousands of people) in terms of the number of years t since the beginning of 2000 would be

g = 7500(1 - 0.036)^t

g = 7500(0.964)^t

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3 years ago