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aivan3 [116]
2 years ago
6

(951² - 159²)÷(7539²-357²) x (258²-852²)

Mathematics
1 answer:
Marysya12 [62]2 years ago
5 0

Answer:

(879,120)÷(56709072) ×(-659340)=-10221.274

Step-by-step explanation:

we use bedmas rules when it comes to long solving questions.

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Please help asap will mark brainlest
JulijaS [17]

Answer: -79, 21, 46, 80

Step-by-step explanation:

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3 years ago
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Use the graph of the function g to answer the following. use correct formatting for your work
netineya [11]

9514 1404 393

Answer:

  • f(-2) = 4
  • f(1) = -5
  • D: [-3, ∞)
  • R: [-5,  11]

Step-by-step explanation:

You have marked the points on the graph corresponding to ...

  f(-2) = 4

  f(1) = -5

__

The domain is the horizontal extent, from x = -3 to +∞.

The range is the vertical extent, from y = -5 to +11 (inclusive).

6 0
2 years ago
What is the solution to the inequality below x^2>81
dem82 [27]

Answer:

x>9

Step-by-step explanation:

4 0
3 years ago
If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly
cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^n-x, where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0
3 years ago
(-6x - 8) - (8x-9) can you subtract the expressions
Tcecarenko [31]

Answer:

-14x+1

Step-by-step explanation:

-6x-8

-8x+9

-14x+1

4 0
2 years ago
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