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3 years ago

Factorise completely 15a^3 - 5abpwease help me

1 answer:

4 0

The first step to factorize is to find the common terms. In this 5a is common throughout. By taking it out we get the expression:

5a (3 a^2 -b)

Hope this helps!

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What is the value of x?

Anastaziya [24]

Answer: 5

Step-by-step explanation:

7 0

2 years ago

Mercedes would like to have an average of 88 in her math class. There are five assignments with the following grades : 85, 100,

vredina [299]

Answer: 80%

Step-by-step explanation:

To find the average, add all the grades and divide by the number of grades

sum of all grades/number of grades

85 + 100 + 88 + 80 + 95 + x/6

She wants to have an 88, so we can set the expression above equal to 88

448 + x/6= 88

Multiply by 6 on both sides

448 + x = 528

Subtract 448 on both sides

x=80

She needs to score at least an 80 to get an 88 average.

Hope this helped!

3 0

3 years ago

What is one-fourth of 24

aev [14]

Answer:

Step-by-step explanation:

One fourth is ÷4

24÷4=6

8 0

3 years ago

Read 2 more answers

Solve the system of linear equations by substituting. Check your solution

Ghella [55]

QUESTION 4

The given system of linear equations are,

$y = 5x - 7...(1)$

and

$- 3x - 2y = - 12...(2)$

We put equation (1) into equation (2) to obtain,

$- 3x - 2(5x - 7) = - 12$

We expand to get,

$- 3x - 10x + 14 = - 12$

Group like terms to get,

$- 3x - 10x = - 12 - 14$

Simplify to get,

$- 13x = - 26$

Divide both sides by -13 to get,

$x = 2$

Put the value of x into equation (1) to get,

$y = 5(2) - 7$

$y = 10 - 7 = 3$

The solution is

$x = 2 \: \: and \: \: = 3$

QUESTION 5

The given system of linear equations are

$-4x+y=6....(1)$
and

$-5x-y=21...(2)$

We make y the subject in equation (1) to get,

$y = 4x + 6....(3)$

Put equation (3) into equation (2) to get,

$- 5x - (4x + 6) = 21$

We expand to get,

$- 5x - 4x - 6 =21$

We group like terms to get,

$- 5x - 4x = 21 + 6$

This implies that,

$- 9x = 27$

We divide both sides by -9 to get,

$x = - 3$

Put the value of x in to equation 3 to get,

$y = 4( - 3) + 6$

$y = - 12 + 6 = - 6$

Therefore the solution is

$x = - 3 \: and \: y = - 6$

QUESTION 6

The given equations are,

$-7x-2y=-13...(1)$

and

$x-2y=-13...(2)$

Make x the subject in equation (2) to get,

$x = 2y - 13...(3)$

Put equation (3) into equation (1) to get,
$- 7(2y - 13) - 2y = - 13$

We expand to get,

$- 14y + 91 - 2y = - 13$

We group like terms to obtain,

$- 14y - 2y = - 13 - 91$

.Simplify to get,

$- 16y = - 104$

Divide through by -16 to get,

$y = \frac{13}{2}$

Put the value of y into equation (3) to get,

$x = 2( \frac{13}{2} ) - 13$

$x = 13 - 13 = 0$

Therefore

$x = 0 \: and \: y = \frac{13}{2}$