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NemiM [27]
3 years ago
12

Martha's bill is $3.37. She pays with a 5 dollar bill. What is the least amount of coins the cashier can give to Martha as chang

e assuming quarters are the highest value coins the cashier has? A 5 B 6 C 2 D 7 E 4
Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

Answer: The answer is d. I think.

Step-by-step explanation:

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Find 5x − 3y − z if x = −2, y = 2, and z = −3<br><br> −19<br> 19<br> 13<br> −13
Blababa [14]
5x - 3y - z
By hypothesis, x = -2, y = 2 and z = -3.

So you all need to do is replace each letter by its value and do the calculus:

5x - 3y - z = 5*(-2) - 3(2) - (-3)
= -10 - 6 + 3=
=-16 + 3
= -13

So when x = -2, y = 2 and z = -3
5x - 3y - z = -13 (answer d)

Hope this helps! :)
8 0
3 years ago
What does the y mean in y=mx+c
zubka84 [21]
<span>y=mx+c
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3 years ago
Work out the size of angle x.<br>X<br>140°<br>105°​
yKpoI14uk [10]

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Step-by-step explanation:

x + 140 + 105 = 180

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x = 180- 245 = - 65

3 0
3 years ago
How to evaluate the limit
anzhelika [568]
\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}

Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
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3 years ago
Find the quotient...<br><br> 3/11 divided by 9/13<br><br> Simplify your answer...
Korvikt [17]
3/11 divided by 9/13 = 3/11 multiplied by 13/9 = 39/99=13/33
5 0
3 years ago
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