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vlabodo [156]
4 years ago
11

Identify the polynomial written in ascending order. (1 point) 3x3− 5x2+ 4x − 7 −5x2+ 4x + 3x3− 7 −7 + 4x − 5x2+ 3x3 4x + 3x3− 7

− 5x2
Mathematics
2 answers:
marta [7]4 years ago
7 0

Keywords:

<em>Polynomial, identify, ascending order</em>

For this case, we must identify the polynomial that is written in ascending order. If we want to order a polynomial of ascending form, we must organize the polynomial from least to greatest exponent. By definition, a polynomial is of the form:

P (x) = ax ^ n + bx ^ {n-1} + ... + cx ^ 3 + dx ^ 2 + ex + f

Where:

a, b, c, d, e, f: They are the coefficients of the polynomial

n, n-1,3,2,1,0: They are the exponents. This polynomial is of degree "n", because "n" is the largest exponent.

x: It is the variable

Then, we must see among the options given a polynomial written from least to greatest exponent, that is, from the form:

P (x) = f + ex + dx ^ 2 + cx ^ 3 + ... + bx ^ {n-1} + ax ^ n

So, among the options we have:

Q (x) = - 7 + 4x-5x ^ 2 + 3x ^ 3 written ascending

Answer:

Option C

IgorC [24]4 years ago
3 0
-7 + 4x - 5x^2 + 3x^3....ascending means smallest to largest
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x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }

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if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0

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