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3 years ago

Which of the following is true for all rectangle

Mathematics

2 answers:

deff fn [24]3 years ago

4 0

Hope this helps good luck!!

trapecia [35]3 years ago

3 0

All rectangles aren't squares but all squares are rectangles. Rectangles have the same sized sides and are simmetrical

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6700 dollars is placed in an account with an annual interest rate of 8%. How much will be in the account after 24 years, to the

daser333 [38]

$\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$6700\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
t=years\to &24
\end{cases}
\\\\\\
A=6700(1+0.08\cdot 24)\implies A=19,564.00$

5 0

3 years ago

Read 2 more answers

Which of the followint iw a linear equation

SpyIntel [72]

Answer:

11.C

12.B

Step by step explanation:

4 0

3 years ago

The distance between itahari and Damak is

Ludmilka [50]

Answer:

8 km by motorbike.

Step-by-step explanation:

The distance between itahari and Damak is 42 km.

Mr. Dhamala travelled 18.325 km by a bus / 15.675 km by a taxi and the remaining distance by a motorbike.

Let he covered x distance by motorbike. So,

Remaining distance = Total distance -(distance covered by bus + distance by taxi)

= 42 -(18.325 +15.675 )

= 42-34

= 8 km

So, he travelled 8 km by motorbike.

8 0

2 years ago

A circle has a diameter of 12 units, and its center lies on the x-axis. What could be the equation of the circle?

ycow [4]

Answer:

$x^{2} +y^{2} =36$

Step-by-step explanation:

A circle centered at (0,0) with radius r is $x^{2} +y^{2} =r^{2}$

Since your circle has diameter of 12, then its radius is 6. Then $r^{2} =36$

So a possible answer is: $x^{2} +y^{2} =36$

If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:

$(x+4)^{2} +y^{2} =36$

The center of this circle would be (-4, 0) which is still on the x-axis.

8 0

3 years ago

Let the smallest of 4 consecutive odd numbers be 2 n + 1 , where n is an integer. Show, using algebra, that the sum of any 4 con

andrey2020 [161]

Answer:

Expression is 8(n+2)

Step-by-step explanation:

smallest of 4 consecutive odd numbers =2n + 1

consecutive odd integers are found by adding 2 to the any given odd numbers

Thus, 2nd consecutive odd integers = 2n + 1 + 2 = 2n + 3

3rd consecutive odd integers = 2n + 3 + 2 = 2n + 5

2nd consecutive odd integers = 2n + 5 + 2 = 2n + 7

Thus, 4 consecutive odd integers are

2n + 1 ,2n + 3,2n + 5,2n + 7

sum of these numbers are = 2n + 1 +2n + 3 + 2n + 5+2n + 7 = 8n+16

sum of these numbers are = 8(n+2)

Thus, we see that the sum of numbers are 8(n+2)

As, 8 is common for n+2, whatever is value of n, the number will be multiple of 8 .

thus expression is 8(n+2)

7 0

3 years ago