Question

How do you know the strength of oxidizing/reducing agents in questions such as these ones? I know the answer for 37 is D but I don’t know why

Answer 1

Answer:

$Pd^{2+}$ is the strongest oxidizing agent .

Explanation:

It is said in the question that given reactions are spontaneous.

As $Np^{3+}$ oxidizes Ce to  $Ce^{3+}$ we can say that  $Np^{3+}$ is a stronger oxidizing agent than  $Ce^{3+}$.

Similarly , $Cd^{2+}$ is stronger than  $Np^{3+}$ (from first reaction).

From second reaction we can see that  $Pd^{2+}$ is stronger than  $Cd^{2+}$.

The order of oxidizing strength is  $Pd^{2+}$ >  $Cd^{2+}$ >  $Np^{3+}$ >  $Ce^{3+}$ .