We have Boltzmann's equation S = k ln W
Boltzmann's constant k = 1.381 x 10^-23 J/K
W = Number of absorption sites
At W = 484, Entropy S1 = 1.381 x 10^-23 ln 484 = 8.537 x 10^-23 J/K
At W = 729, Entropy S2 = 1.381 x 10^-23 ln 729 = 9.103 x 10^-23 J/K
Change of Entropy = S2 - S1 = 0.566 x 10^-23 J/K
Answer:
A: 11 protons and 21 neutrons
Explanation:
Hopefully this helps!
If an atom lose 2 electrons it will give Ion with 2+ charge called cation
The expression for the Ka for the given acid is:
Ka = [H2P2O7^2-] [H3O+] /[H3P2O7^2-]
Ka is the acid dissociation constant or the acidity constant. It is a measure of the acid strength when in solution. It is an equilibrium constant for the dissociation of the acid.
The nucleophile used to react with butyl iodide to form te compound below is :
<h3>What is a Nucleophile </h3>
A Nucleophile is a molecule in a chemical reaction that seeks for a positive center of the reaction ( i.e. nucleus ) and this is because of the presence of a electron pair in the Nucleophile.
Given the compound expressed in the question the chemical reaction that takes place between the nucleophile and butyl iodide is called Nucleophilic substitution reaction.
Hence we can conclude that the nucleophile that could be used to react with butyl iodide is CH₃CH₂O⁻
Learn more about Nucleophile : brainly.com/question/9126498
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