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Inessa [10]
3 years ago
15

0.000000000009256 scientific method

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0

Answer:

9.256×10^−12

Step-by-step explanation:

to get standard notation we have a number less ten.

since it is a very small number it has a negative exponent

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80 POINTS ! Use the image below to answer the following question. What relationship do the ratios of sin x° and cos y° share?
nordsb [41]

Answer:

A) The ratios are both identical (3/5 and 3/5)

Step-by-step explanation:

x:-

3 = opposite

5= hypotenuse

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8 0
3 years ago
(11m-7m)-(2m+6m) the sum or differce
Bingel [31]

Answer:

-4m

Step-by-step explanation:

=11m-7m-(2m+6m)

=11m-7m-8m

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5 0
3 years ago
Read 2 more answers
A rectangular field is 75 yards wide and 105 yards long
nika2105 [10]

Answer:

width = 72 yards

length = 108 yards

Step-by-step explanation:

Given:

  • Width = 75 yards
  • Length = 105 yards

<u>Area of the field</u> with the given values:

\begin{aligned}\textsf{Area of a rectangle}&=\sf width \times length\\& = \sf 75 \times 105\\& = \sf 7875\:\: yd^2\end{aligned}

To maintain the <u>same perimeter</u>, but <u>change the area</u>, either:

  • decrease the width and increase the length by the same amount, or
  • increase the width and decrease the length by the same amount.

In geometry, length pertains to the <u>longest side</u> of the rectangle while width is the <u>shorter side</u>.  Therefore, we should choose:

  • decrease the <u>width</u> and increase the <u>length</u> by the <u>same amount</u>.

<u>Define the variables</u>:

  • Let x = the amount by which to decrease/increase the width and length.

Therefore:

\implies \sf width \times length < 7875\:\:yd^2

\implies (75-x)(105+x) < 7875

Solve the inequality:

\begin{aligned}(75-x)(105+x) & < 7875\\7875-30x-x^2 & < 7875\\-x^2-30x & < 0\\-x(x+30) & < 0\\x(x+30) & > 0\\\implies x & > 0 \:\: \textsf{ or }\:\:x < - 30\end{aligned}

Therefore, as distance is positive only and the maximum width is 75 yd (since we are subtracting from the original width):

\begin{cases}\textsf{width} = 75 - x\\\textsf{length} = 105 + x\end{cases}

\textsf{where } 0 < x < 75

Therefore, to find the width and length of another rectangular field that has the same perimeter but a smaller area than the first field, simply substitute a value of x from the restricted interval into the found expressions for width and length:

<u>Example 1</u>:

  • Let x = 3

⇒ Width = 75 - 3 = 72 yd

⇒ Length = 105 + 3 = 108 yd

⇒ Perimeter = 2(72 + 108) = 360 yd

⇒ Area = 72 × 108 = 7776 yd²

<u>Example 2</u>:

  • Let x = 74

⇒ Width = 75 - 74 = 1 yd

⇒ Length = 105 + 74 = 179 yd

⇒ Perimeter = 2(1 + 179) = 360 yd

⇒ Area = 1 × 179 = 179 yd²

4 0
1 year ago
Read 2 more answers
Amy is biking to school from her father's house and Jeremy is biking to school from his aunt's house. Suppose Amy is moving at a
Mrrafil [7]

Answer:

No.

Step-by-step explanation:

Since we do not know the location of each house in relation to the school, we cannot figure out who is goona arive faster

4 0
3 years ago
PLSSS HELP! Can someone pls tell me how to do this. y=1/3(x+2)^2, y=x+3
Leokris [45]

Answer:

There you go.

Step-by-step explanation:

Please do tell me if it's wrong.

7 0
3 years ago
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