Answer:
perpetual motion machine of second type is a machine that generates job from a single source of heat.
Explanation:
perpetual motion machine is a machine that generates job from a single source of heat. only one heat reservoir is present in this type of machine and it is continuously cooled to generate function without transferring heat to a cooler reservoir. Such a demonstration machine was names as ammonia engine
The sample of 81 students was selected with a mean score of 90, this illustrates an example of a right tailed one sample z test.
<h3>How to illustrate the sample?</h3>
From the information given, the teacher claims that the mean score of students in his class is greater than 82 with a standard deviation of 20. In this case, the right tailed one sample z test is used.
The z value will be:
= (90 - 82)/20/✓81
= 3.6
Since 3.6 > 1.645, the null hypothesis will be rejected as there's enough evidence to support the teacher's claim.
When an online medicine shop claims that the mean delivery time for medicines is less than 120 minutes with a standard deviation of 30 minutes, the left tailed one sample test is used.
The z value will be:
= (100 - 120)/(30/✓49)
= -4.66
The null hypothesis is rejected as there is enough evidence to support the claim of the medicine shop.
Learn more about sampling on:
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Answer:
umax = 0.1259ft/s
Explanation:
Given:
•Distance between plates, B = 0.01ft
•Pressure difference decrease, 
•Fluid viscosity, u = 10^-³lbf-s/ft²
Specific gravity, S = 0.80
Max velocity in the z-direction will be:
![u_max= [\frac{B^2y}{8u}]\frac{dh}{ds}](https://tex.z-dn.net/?f=u_max%3D%20%5B%5Cfrac%7BB%5E2y%7D%7B8u%7D%5D%5Cfrac%7Bdh%7D%7Bds%7D)
Substituting for h in the first equation, we have:
![\frac{d}{dz}[\frac{p}{y}+z]](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdz%7D%5B%5Cfrac%7Bp%7D%7By%7D%2Bz%5D)
= -0.20192
Substituting dh/dz value in the first equation (umax), we have:
umax = 0.1259ft/s
Answer:
a) the log mean temperature difference (Approx. 64.5 deg C)
b) the rate of heat addition into the oil.
The above have been solved for in the below workings
Explanation:
