Question

If you know that the change in entropy of a system where heat was added is 12 J/K, and that the temperature of the system is 250 K, what is the amount of heat added to the system? a)-5J b)-125J c)- 600 J d)-5000 J e)-8000 J

Answer 1

Solution:

Given:

Change in entropy of the system, ΔS = 12J/K

Temperature of the system, $T_{o}$ = 250K

Now, we know that the change in entropy of a system is given by the formula:

ΔS = $\frac{\Delta Q}{T_{o}}$

Amount of heat added, ΔQ = $\Delta S\times T_{o}$

ΔQ = 3000J