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Katyanochek1 [597]
3 years ago
9

Someone please help please I really need this

Mathematics
1 answer:
Aneli [31]3 years ago
7 0

x = \dfrac{1}{4}x+\dfrac{3}{4}\ \ \ \ |-\dfrac{1}{4}x\\\\\dfrac{3}{4}x=\dfrac{3}{4}\ \ \ \text{ONE SOLUTION}\\\\\dfrac{1}{2}(1+4x)=2x-3\\\\\dfrac{1}{2}+2x=2x-3\ \ \ \ |-2x\\\\\dfrac{1}{2}=-3\ \ \ \ \text{NO SOLUTION}\\\\\dfrac{1}{3}x-5=\dfrac{2}{3}x-5\ \ \ \ |-\dfrac{2}{3}x\\\\-\dfrac{1}{3}x-5=-5\ \ \ \ \ \text{ONE SOLUTION}\\\\3-4x=-6\left(\dfrac{2}{3}x-\dfrac{1}{2}\right)\\\\3-4x=-4x+3\ \ \ \ |+4x\\\\3=3\ \ \ \ \ \text{INFINITELY MANY SOLUTIONS}

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<em><u>B. Store T sells apples at the lowest rate</u></em>

Step-by-step explanation:

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To find the answer, <u>you have to find the unit price</u> for both Store S and Store T.

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For Store T: 3 pounds = $3.48. Same thing as Store S, d<u>ivide the cost by the number of pounds</u>. This will give us <u>1.16 per pound</u>.

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A. Store R sells apples at the lowest rate.

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B. Store T sells the apples at the lowest rate.

This answer is <em><u>correct</u></em>, but I'll also take a look at the other two

C. Store S charges a lower rate for apples than Store T.

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D. Store T charges the same rate for apples as Store R.

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