$\bf ~\hspace{10em}1\le x\le 5~\hspace{5em}\sqrt{x^3+36}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\sqrt{x^3+36}\implies \sqrt{x^{2+1}6^2}\implies \sqrt{x^2x6^2}\implies \sqrt{(6x)^2x}\implies 6x\sqrt{x}
\\\\\\
\stackrel{\textit{x = 4}}{6(4)\sqrt{4}}\implies 24\sqrt{2^2}\implies 24\cdot 2\implies 48$

that's how I read it.... to get some value between 1 and 5, namely 4, to make the expression a rational, well, 48 can be expressed as 48/1.

7 0

3 years ago

Y = 119.67 (0.61) ÷ 5

Travka [436]

Y= 119.67 (0.61) <span>÷ 5
Y= 72.9987 </span>÷ 5 or 73 ÷ 5<span>
Y= 14.6</span>

4 0

3 years ago