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Dafna1 [17]
3 years ago
13

The coordinates of the endpoints of line segment C D are C(3, 8) and D(6, -1). Express the length of line segment C D in simples

t radical form.
Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
C&({{ 3}}\quad ,&{{ 8}})\quad 
%  (c,d)
D&({{ 6}}\quad ,&{{ -1}})
\end{array}\qquad 
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
CD=\sqrt{(6-3)^2+(-1-8)^2}\implies CD=\sqrt{3^2+(-9)^2}
\\\\\\
CD=\sqrt{9+81}\implies CD=\sqrt{90}\quad 
\begin{cases}
90=2\cdot 3\cdot 3\cdot 5\\
\qquad 2\cdot 3^2\cdot 5\\
\qquad 10\cdot 3^2
\end{cases}
\\\\\\
CD=\sqrt{10\cdot 3^2}\implies CD=3\sqrt{10}
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Answer:

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Step-by-step explanation:

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Answer:

D. \frac{4x^{2} \sqrt{29}}{29}

Step-by-step explanation:

Given the expression:

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divide by the common factor to have;

\frac{4\sqrt{x^{12} } }{\sqrt{29x^{8} } } = \frac{4(x^{12}) ^{\frac{1}{2} } }{(29x^{8}) ^{\frac{1}{2} } }

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        = \frac{4x^{2} }{\sqrt{29} }

Rationalize the denominator, we have;

\frac{4x^{2} }{\sqrt{29} } x \frac{\sqrt{29} }{\sqrt{29} }

So that,

\frac{4x^{2} \sqrt{29} }{29}

Thus,

\frac{40x^{2} \sqrt{x^{12} } }{10x^{2} \sqrt{29x^{8} } } = \frac{4x^{2} \sqrt{29} }{29}

The correct option is D.

5 0
3 years ago
If n,6 M are in geometric sequence n,7.5, m are in arithmetic sequence ,then find the value of n and m?​
hjlf

Answer:

if  n,6,m are in geometric sequence

=> 6/n = m/6

⇔ mn = 36       (1)

if n,7.5, m are in arithmetic sequence

=> 7.5 - n = m - 7.5

<=> m + n = 15     (2)

from (1)(2), we have the equations:

\left \{ {{mn=36} \atop {m+n=15}} \right.\\\\\left \{ {{mn=36} \atop {m=15-n}} \right.\\\\\left \{ {{(15-n)n=36} \atop {m=15-n}} \right.\\\\\left \{ {{n^{2}-15n+36 =0} \atop {m=15-n}} \right.\\\\\left \{ {{n=12orn=3} \atop {m=15-n}} \right.

with n = 12 => m = 3

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=> (m;n) = {(3;12),(12;3)}

Step-by-step explanation:

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