What is 3 to the 6th power to the negative 2

Mathematics

1 answer:

malfutka [58]3 years ago

8 0

I believe the answer is 1/531441

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A telephone survey uses a random digit dialing machine to call subjects. the random digit dialing machine is expected to reach a

yanalaym [24]

P( $r$ successes in $n$ trials) = ⁿ $C_{r}$ × $[P(Success)^{r}]$ × $[P(failure)]^{n-r}$

We have
$n=8$
$r=2$
$P(Success)=0.15$
$P(Failure)=0.85$

Substitute these values into the formula, we have
P( 2 success in 8 trials) = ⁸C₂ × (0.15)² × (0.85)⁶
P( 2 success in 8 trials) = 0.2376.... ≈ 0.24 = 24%

6 0

3 years ago

Which is the solution set of the compound inequality 3.5x - 10 > -3 and 8x - 9 < 39

ludmilkaskok [199]

Hello! So, for the first inequality, we have to add 10 to both sides. When you do that, 3.5x > 7. Then, you have to divide both sides by 3.5. When you do that, you get x > 2. Then, for the second inequality, you have to add 9 to both sides, then you would get 8x < 48. Divide both sides by 8 and you get x < 6. The compound inequality for this question would be 2 < x < 6.

3 0

4 years ago

How to find variables of these #2 & #3

Lubov Fominskaja [6]

So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}$

now.. for 3) will be the second picture below

$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}$