What is 3 to the 6th power to the negative 2

Answer plz!<br> Which choices are equivalent to the expression below? Check all that apply.

ziro4ka [17]

A, B and C but I’m contemplating D too but it’s def not E or F

4 0

2 years ago

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Which function describes this table of value x -8, -4, 4, 8, y -2, 0, 4, 6

nadezda [96]

we conclude that the linear equation represented by the given table is:

y = (1/2)*x + 2

<h3>Which function is the one described by the table?</h3>

A general linear equation is given by:

y = a*x + b

Where a is the slope and b is the y-intercept.

If the line passes through (x₁, y₁) and (x₂, y₂), then the slope is given by:

$a = \frac{y_2 - y_1}{x_2 - x_1}$

Here we can use just the first two points on the given line:

(-8, -2) and (-4, 0)

Then the slope will be:

$a = \frac{0 - (-2)}{-4 -(-8)} = \frac{2}{4} = \frac{1}{2}$

Then the linear equation is something like:

y = (1/2)*x + b

To find the value of b, we can use one of the two given points, I will use (-4, 0), then:

0 = (1/2)*(-4) + b

0 = -2 + b

2 = b

Then we conclude that the linear equation represented by the given table is:

y = (1/2)*x + 2

Then the correct option is the first one.

If you want to learn more about linear equations:

brainly.com/question/1884491

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8 0

1 year ago

yo can someone pls help me with this i’ve been crying for the last hour bc i can’t figure it out and it’s due in 30 minutes. the

mr Goodwill [35]

9514 1404 393

Answer:

area: 524 cm²
perimeter: 124.8 cm

Step-by-step explanation:

The rectangle in the middle has a width equal to the radius of the semicircular ends, so (20 cm)/2 = 10 cm.

The semicircular ends, together, make a complete circle of radius 10 cm.

The area is the sum of the areas of the parts:

A = LW = (21 cm)(10 cm) = 210 cm² . . . . . . rectangle area

A = πr² = π(10 cm)² = 100π cm² ≈ 314 cm² . . . . . circle area

The total area is ...

210 cm² +314 cm² = 524 cm² . . . . area of the figure

__

The perimeter of the figure is the sum of the lengths of all of the edges. From the left, working clockwise, we have ...

P = (1/2 circle of diameter 20) + (rectangle top = 21) +(1/2 circle of diameter 20) +(circle radius = 10) +(rectangle bottom = 21) +(circle radius = 10)

The two 1/2 circles add to a whole circle with a circumference of ...

C = πd = (3.14)(20 cm) = 62.8 cm

Then the whole perimeter is ...

P = 62.8 cm + 21 cm + 10 cm + 21 cm + 10 cm = 124.8 cm

_____

Note that we have used 3.14 for pi. If you use a more exact value, your answers will be slightly different.

4 0

2 years ago

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of

iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is $\\ P(z>0.48) = P(x>533.2) = 0.3156$

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a <em>sample mean</em>. The distribution for <em>sample means</em> follows a <em>normal distribution</em> with mean $\\ \mu$ and standard deviation $\\ \frac{\sigma}{\sqrt{n}}$ . Mathematically

$\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

For values of the sample $\\ n \ge 30$ , no matter the distribution the data come from.

And the variable <em>z</em> follows a <em>standard normal distribution</em>, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [1]

That is

$\\ z \sim N(0, 1)$

We have a variance of 3364. That is, a <em>standard deviation</em> of

$\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58$

The population mean is

$\\ \mu = 530$

The sample size is $\\ n = 75$

The sample mean is $\\ \overline{x} = 533.2$

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}$

$\\ z = \frac{3.2}{\frac{58}{8.66025}}$

$\\ z = \frac{3.2}{6.69726}$

$\\ z = 0.47780$

With this value of z we can consult a <em>cumulative standard normal table</em> (or use some statistic program) to find the cumulative probability for <em>z</em> (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

$\\ P(z$

However, in the question we are asked for $\\ P(z>0.48) = P(x>533.2)$ . As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

$\\ P(z>0.48) = 1 - P(z$

Thus

$\\ P(z>0.48) = 1 - 0.68439$

$\\ P(z>0.48) = 0.31561$

Rounding to four decimal places, we have

$\\ P(z>0.48) = 0.3156$

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) $\\ P(z>0.48) = P(x>533.2) = 0.3156$ .

5 0

3 years ago

Someone help me Solve x

nekit [7.7K]

Answer:

Step-by-step explanation:

<h2>Hope this helps</h2><h2>I would explain but I have some work so sorry</h2>

3 0

2 years ago

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