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4 years ago

6

Whoever good at math plss help me

1 answer:

dangina [55]4 years ago

3 0

What you have to do is post your math question on here.

Or DM it for extra help if you prefer

You might be interested in

what is the sum of the first five ferms of a geometric series with a1=10 and r=1/5? express your answer as an important fraction

mote1985 [20]

The sum of any geometric sequence, (technically any finite set is a sequence, series are infinite) can be expressed as:

s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=term number

Here you are given a=10 and r=1/5 so your equation is:

s(n)=10(1-(1/5)^n)/(1-1/5) let's simplify this a bit:

s(n)=10(1-(1/5)^n)/(4/5)

s(n)=12.5(1-(1/5)^n) so the sum of the first 5 terms is:

s(5)=12.5(1-(1/5)^5)

s(5)=12.496

as an improper fraction:

(125/10)(3124/3125)

390500/31240

1775/142

6 0

3 years ago

2. Flying to Kampala with a tailwind a plane averaged 158 km/h . On the return trip the plane only averaged 112 km/h while flyin

stiv31 [10]

Answer:

Speed of plane in still air = 135 km/h

Speed of wind = 23 km/h

Step-by-step explanation:

Given that:

Speed of plane with the wind = 158km/h

Speed of plane against the wind = 112km/h

Let,

x be the speed of plane

y be the speed of wind

According to given statement;

x+y = 158 Eqn 1

x-y = 112 Eqn 2

Adding Eqn 1 and 2

$x+y+x-y=158+112\\2x = 170\\\frac{2x}{2}=\frac{270}{2}\\x=135$

Putting x = 135 in Eqn 1

135+y = 158

y = 158-135

y = 23

Hence,

Speed of plane in still air = 135 km/h

Speed of wind = 23 km/h

8 0

3 years ago

At a movie theater, admission tickets cost $10 for adults and $8 for children. On Saturday, Anne Teak collected a total of $1276

kow [346]

Answer:

Part a) variable x (the number of adult tickets sold) and variable y (the number of child tickets sold)

Part b) $10x+8y=1,276$

Part c) The number of adult tickets sold was 86

Step-by-step explanation:

Part a) Name a variable for the number of adult tickets sold and name a variable for the number of child tickets sold

Let

x -----> the number of adult tickets sold

y -----> the number of child tickets sold

Part b) Write an equation in two variables to model the problem

we know that

$10x+8y=1,276$ -----> equation A

$y=52$ -----> equation B

substitute equation B in equation A and solve for x

$10x+8(52)=1,276$

$10x+416=1,276$

Part c) Using your equation in Part B, solve the problem and answer the question "how many adult tickets did Anne sell?" i

we have

$10x+416=1,276$

Solve for x

Subtract 416 both sides

$10x=1,276-416$

$10x=860$

$x=86$

therefore

The number of adult tickets sold was 86

7 0

4 years ago

Please help me123456

Zanzabum

Answer:

the answer of the question is 9.5

4 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST IF RIGHT PLZ HELP!!!

Komok [63]

Answer:

-24

Step-by-step explanation:

you're welcome

6 0

3 years ago