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Mandarinka [93]
3 years ago
6

How many numbers between 40 and 129 are equal to 6 times an integer

Mathematics
1 answer:
Pavel [41]3 years ago
7 0
Here, the series would be: 42, 48 .... 126
an = a + (n - 1)d
126 = 42 + (n - 1)6
126 - 42 = 6n - 6
84 + 6 = 6n
n = 90/6
n = 15

In short, Your Answer would be 15

Hope this helps!

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STEP - BY - STEP EXPLANATION

What to find?

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Given:

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Step 1

Draw a sketch.

Step 2

Substitute the values into the trig. ratio formula below.

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From the sketch above, opposite = 3 and adjacent = 4

tan\theta=\frac{3}{4}

Step 3

Find the value of the hypotenuse side using Pythagoras theorem.

let h be the hypotenuse side.

\begin{gathered} h^2=4^2+3^2 \\  \\ =16+9 \\  \\ =25 \\  \\ h=5 \end{gathered}

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Step 4

Substitute the values into the formula below:

\begin{gathered} cos\theta=\frac{adjacent}{hypotenuse} \\  \\ =\frac{4}{5} \end{gathered}

But,

sec\theta=\frac{1}{cos\theta}=\frac{1}{\frac{4}{5}}=\frac{5}{4}

ANSWER

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