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Bingel [31]
3 years ago
12

What is the following sum ?

Mathematics
2 answers:
Goryan [66]3 years ago
6 0
Look at the expressions inside the brackets - they are the same!! basically you have an equation in the form of
4a + 3a
where
a= ( \sqrt[5]{ {x}^{2}  {y} } )

the answer is the 3rd option.
Gwar [14]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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A nursery owner buys 5 panes of glass to fix some damage to her greenhouse. The 5 panes cost ​$12.25. ​Unfortunately, she breaks
Ksju [112]

Answer:

it would be $4.90

Step-by-step explanation:

12.25/5 is 2.45 per pane

4 0
2 years ago
How to simplify 20/10
Andreyy89

In order to get the answer to this question you will have to find the common factor and then divide the numerator and denominator by the common factor to get the answer.

\frac{20}{10}

CF=10

20\div10=2

10\div10=1

\frac{2}{1} =2

= \frac{2}{1} or2

Therefore the answer is "2."

Hope this helps.

4 0
3 years ago
The answer to this problem for math home work
coldgirl [10]
A is the correct answer.
5 0
3 years ago
What is the fraction of 28 and 8
vazorg [7]

Can you add more information?

4 0
3 years ago
I need help with #8. I need to use the quadratic formula. I have a calculator that is programmed for the quadratic formula so al
GuDViN [60]

Answer:

  x = 14

Step-by-step explanation:

Extend line AB so that it intersects ray CE at point G. Then angles BGC and BAD are "alternate interior angles", hence congruent.

The angle at B is exterior to triangle BCG, and is equal to the sum of the interior angles at C and G:

  138 = (376 -23x) +(x^2 -8x)

Subtracting 138 and collecting terms we have ...

  x^2 -31x +238 = 0

For your calculator, a=1, b=-31, c=238.

__

<em>Additional comment</em>

You will find that the solutions to this are x = {14, 17}. You will also find that angle BCE will have corresponding values of 54° and -15°. That is, the solution x=17 is "extraneous." It is a solution to the equation, but not to the problem.

For x=14, the marked angles are A = 84°, C = 54°.

8 0
3 years ago
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