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crimeas [40]
3 years ago
9

Calculate how much an astronaut with mass of 90 kg would weigh while standing on the surface of Mars. The acceleration due to gr

avity on Mars is approximately 3.7 m/s^2. Express your answer in Newtons. Show your work
Physics
1 answer:
Mars2501 [29]3 years ago
6 0

The weight of anything is

(the thing's mass) times (gravity in the place where the thing is located).

Gravity on Earth is 9.8 m/s
² .
90 kg of mass weighs  (90 kg) · (9.8 m/s²)  =  882 Newtons on Earth.

Gravity on the Moon is 1.62 m/s² .
The same 90 kg weighs (90 kg)·(1.62 m/s²) = 146 Newtons on the Moon.

Gravity on Mars is 3.7 m/s² .
The same 90 kg of mass weighs (90 kg)·(3.7 m/s²) = 333 Newtons on Mars.
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The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

4 0
3 years ago
A 5 kg ball rolling at 1.0 m/s hits a 15 kg ball at rest. The balls stick together after the collision What is the
Reika [66]

Answer:

0.25m/s

Explanation:

Given parameters

m₁  = 5kg

v₁ = 1.0m/s

m₂ = 15kg

v₂ = 0m/s

Unknown:

velocity after collision = ?

Solution:

Momentum before collision and after collision will be the same. For inelastic collision;

    m₁v₁ + m₂v₂  = v(m₁ + m₂)

Insert parameters and solve for v;

   5 x 1  + 15 x 0 = v (5 + 15 )

          5  = 20v

          v = \frac{5}{20}   = 0.25m/s

5 0
3 years ago
Which of the the following distance vs time graphs represents an object the is moving at constant non zero velocity
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A graph with a horizontal line
8 0
3 years ago
) In the figure below, three charges K, L and M are placed at the corners of an equilateral triangle. If K and L are fixed, in w
abruzzese [7]

Answer:

B)

Explanation:

Negative (-) charge M will not move towards negative (-) charge K because, same charges will not attract each other in the given case

Negative (-) charge at the M tends to move towards positive (+) charge L in the direction of B) because opposite charges attract each other.

4 0
2 years ago
HELP ASAP‼️<br><br> Can someone please answer this question I’m confusion❔
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the enclosed may help. earth rotes and you and i are fixed to it. air flows it's own path ...

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