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eimsori [14]
3 years ago
10

An electromagnetic wave moves through electric and magnetic fields. How might the movement of the wave be described?

Physics
1 answer:
Elenna [48]3 years ago
7 0

A. The vibrations of the fields are perpendicular to the direction in which the wave moves.

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When a pitcher throws a baseball, it reaches a top speed of 39 m/s. if the
Aliun [14]

From the calculation, the acceleration of the body is 26m/s^2.

<h3>What is motion under gravity?</h3>

When an object is thrown up or down, the motion of the body is influenced by the gravitational pull on the body.

Now;

Given that;

v = 39 m/s

t = 1.5 s

u = 0 m/s

a = ?

v = u + at

v = at

a = v/t

a = 39 m/s/1.5 s

a = 26m/s^2

Learn more about acceleration:brainly.com/question/12550364

#SPJ1

4 0
2 years ago
While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.
lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

6 0
3 years ago
A tension of 35.0N is applied downward on a 2.50kg mass. What is the acceleration of the mass?
Assoli18 [71]

Answer:

D. -23.8 m/s2​

Explanation:

3 0
3 years ago
Read 2 more answers
Two identical billiard balls are rolling toward each other at the same speed. What will be true after they collide head-on?
tino4ka555 [31]

Answer:

They will both bounce back at the same speed they had before the collision

Explanation:

Assuming an elastic collision, kinetic energy will be conserved.  Therefore, the billiard balls will have the same speed after the collision as before the collision.

7 0
3 years ago
I AM GIVING 95POINTS HELP PLEASE!!
Firlakuza [10]

25,000 Feet = 7620m


PE = mgh where m is mass, g is gravity accel: 9.8 n h is height


= 90 x 9.8 x 7620


= 6720840J


= 6.72MJ


F = ma where m is mass, a is accel = gravity = 9.8


= 90 x 9.8


= 882N


Accel = gravity = 9.8m/s^2


KE = 1/2mv^2 where m is mass n v is vel


if no wind resistance, PE leaving airplane = KE at net


6720840 = 1/2 x 90 x v^2


v^2 = 149352


v = 386.5m/s


150MPH=67m/s


@150MPH, his speed is not changing so accel=0


accel=0, force=0 by newton's second law


force=0 when wind resistance = gravity = 9.8m/s^2


by conservation of energy, Luke's KE = PE = mgh = 6720840J


he was unhurt cuz' his momentum was absorbed by the net

3 0
3 years ago
Read 2 more answers
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