Ask question

Ask question

All categories

3 years ago

5

Joe has a mass of 40 kg, and Sally has a mass of 25 kg. They sit in class with a separation of 6 meters. Find the gravitational

attraction between Joe and Sally.

1 answer:

goldfiish [28.3K]3 years ago

4 0

Answer:

hmmmmmmmm

Explanation:

mmmmmmmmmmmmmmmmmmmmmmm pay attention in class kid

You might be interested in

The student used two different types of thermometer to measure the temperature

iris [78.8K]

0.02 °C is the resolution of thermometer B while measuring temperature.

Thermometer A= 87.6

Thermometer B=87.4°C

resolution= 87.6- 87.4°C = 0.02 °C

Heat or cold are measured in terms of temperature. It can be defined in terms of a variety of arbitrary scales and shows how heat energy naturally moves from a hotter to a cooler substance (one at a lower temperature). Even if a match burns at a considerably greater temperature than an iceberg, an iceberg has a much higher overall heat energy. The energy of a thermodynamic system differs from temperature.

Temperature, along with pressure, density, and other related qualities, is referred to as an intense property—one that is independent of the amount of material being addressed—in contrast to broad characteristics like mass or volume.

To know more about temperatures visit : brainly.com/question/14161300

#SPJ1

5 0

10 months ago

Find the unbalanced force required to accelerate a 6kg mass at 3ms

Mila [183]

Force (F)=Mass (m)×Acceleration (a).

∴F=ma.

∴F=(2kg)×(3ms2).

∴F=6kgms2=6 Newton. =6N.

5 0

3 years ago

When light reflects on a mirror, does it undergo a phase change?

Lynna [10]

The light does not undergo a phase change.

Also, the surface of a mirror is a rigid boundary.

5 0

2 years ago

Cart 1 has a mass of 1 kg. Cart 2 has a mass of 2 kg. They are pushed apart by a spring. The spring exerts 2N of force into cart

almond37 [142]

The force exerted on the cart 2 during the collision is 2 N.

The given parameters:

<em>Mass of cart 1 = m1 = 1 kg</em>
<em>Mass of cart 2 = m2 = 2kg</em>
<em>Force applied on cart 1 = 2 N</em>

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.

$F_1 = -F_2$

$F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N$

Thus, the force exerted on the cart 2 during the collision is 2 N.

Learn more about Newton's third law of motion here: brainly.com/question/13874955

5 0

2 years ago

A 6.0 kg bowling ball moving at 3.5m/s to the right makes a collision, head-on, with a stationary 0.70 kg bowling pin. If the ba

devlian [24]

Answer:

The velocity of the pin will be 6.26 m/s in the right direction.

Explanation:

Let's use the momentum conservation equation.

$p_{i}=p_{f}$

Initially, we have:

$p_{i}=m_{b}*v_{ib}$

Where:

m(b) is the ball mass
v(ib) is the initial velocity of the ball

Now, the final momentum will be:

$p_{f}=m_{b}*v_{fb}+m_{p}*v_{fp}$

Where:

m(p) is the pin mass
v(fb) is the final velocity of the ball

v(fp) is the final velocity of the pin

Then, using the equation of the conservation we have:

$m_{b}*v_{ib}=m_{b}*v_{fb}+m_{p}*v_{fp}$

$6*3.5=6*2.77+0.7*v_{fp}$

$6*3.5=6*2.77+0.7*v_{fp}$

$v_{fp}=6.26 m/s$

Therefore the velocity of the pin will be 6.26 m/s in the right direction.

I hope it helps you!

4 0

3 years ago