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Reika [66]
4 years ago
6

Distribute to simplify the expression: 3 ( 2X + 5Y - 4)

Mathematics
2 answers:
IrinaK [193]4 years ago
8 0

Answer:

6X + 15Y - 12

Step-by-step explanation:

3 (2X + 5Y - 4)

Multiply each term by 3

2X * 3 + 5Y * 3 - 4 * 3

6X + 15Y - 12

Yakvenalex [24]4 years ago
6 0

Answer:

6x+15y-12

Step-by-step explanation:

3(2x+5y-4)

1) Distribute the 3 to 2x, 5y, and -4:  (Multiply the values together!)

6x+15y-12

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Each earbud is 4/7 of an inch long. If you put 8 earbuds end to end, how long would they be from beginning to end?​
Lisa [10]

Answer:

4 4/7

Step-by-step explanation:

4/7x8/1

4x8/7x1

32/7

4 4/7

6 0
3 years ago
Read 2 more answers
Identify the percent of change an increase or decrease then find percent of change one hundredfifty pounds to one hundred thirty
Alex777 [14]

Answer:

−10%change

 10%decrease

Step-by-step explanation:

V2−V1)|V1|×100

 =(135−150)|150|×100

=−15150×100

=−0.1×100

=−10%change

=10%decrease

Note: Percent Change is NOT the same as  Percent Difference between 150 and 135.

Hope this helps!

6 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Will mark as brainliest! <br> Btw, it’s not D
Elanso [62]

Answer:

The IQR is a better measure of spread for movies than it is for basketball games

Step-by-step explanation:

The Basket ball games has no outliers so we would use standard deviation as the measure of spread.  The movies has an outlier so we would use IQR as the measure of spread.

6 0
3 years ago
The factor tree below provides the factors of 18. What is the prime factorization of 18?
Softa [21]
The prime factorization of 18 is
   2 × 3²

____
You could read this from the factor tree by looking at the leaves.
4 0
3 years ago
Read 2 more answers
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