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Ahat [919]
4 years ago
13

14+3x−7=7x+7−4x14+3x-7=7x+7-4x is always, sometimes or never true.

Mathematics
2 answers:
Alona [7]4 years ago
7 0
Sometimes because 7x2 equals 14 and 7x3 equals 21 and it's not 14+3x-7 sorry if not true because it's algebra I think
Serjik [45]4 years ago
4 0
Sometimes  i think because if it uses the communitive property it is sometimes
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Reduce to simplest form.
Shkiper50 [21]

Answer:

  11/6

Step-by-step explanation:

  \dfrac{6}{3}+\left(-\dfrac{1}{6}\right)=\dfrac{12}{6}-\dfrac{1}{6}=\dfrac{12-1}{6}\\\\=\boxed{\dfrac{11}{6}}

As a mixed number, this is 1 5/6.

3 0
3 years ago
1/5 fraction as demicals​
wolverine [178]

Answer:

the answer of this question will be 0.2

7 0
3 years ago
Read 2 more answers
In a state where license plates contain six digits, what is the probability that the license number of a randomly selected car h
andre [41]

Answer:

Step-by-step explanation:

Given : In a state where license plates contain six digits.

Probability of that a number is 9 = \dfrac{1}{10}   [Since total digits = 10]

We assume that each digit of the license number is randomly selected  .

Since each digit in the license plate is independent from the other  and there is only two possible outcomes for given case (either 9 or not), so we can use Binomial.

Binomial probability formula:  P(X=x)=^nC_xp^x(1-p)^{n-x}

, where n= total trials , p = probability for each success.

Let x be the number of 9s in the license plate number.

X\sim Bin(n=6, p=\dfrac{1}{10}})

Then, the probability that the license number of a randomly selected car has exactly two 9's will be :

P(X=2)=^6C_2(\dfrac{1}{10})^2(1-\dfrac{1}{10})^{6-2}\\\\=\dfrac{6!}{2!(6-2)!}(\dfrac{1}{100})(\dfrac{9}{10})^4=0.098415

Hence, the required probability = 0.098415

5 0
3 years ago
Each marble bag sold by hans marble company contains 7 yellow marbles for every 5 blue marbles. if a bag has 35 blue marbles, ho
Pavlova-9 [17]
The answer is 49 because since she multiplied 5 by 7 you have to do the same to yellow marbles so 7×7 = 49
5 0
4 years ago
Solve the system of equations. y = -5x + 24 y = 4x - 21 a. ( -5, -1) c. ( -1, 5) b. ( 5, -1) d. No solution
Svetlanka [38]

y = -5x + 24

y = 4x - 21

Since both of these equations are equal to Y, theyre equal to each other.

So we can make an equation with y = -5x + 24 in one side and y = 4x - 21 on the other.

-5x + 24 = 4x - 21

Now in order to get the value of x we need to isolate it in one side of the equation. We can do this by subtracting 24 from both sides of the equation:

-5x + 24 - 24 = 4x - 21 - 24

-5x = 4x - 45

Now we subtract 4x from both sides so the 4x shift to the other side

-5x - 4x = 4x - 4x - 45

-9x = -45

Finally divide both sides by -9 so x is by itself

(-9)÷(-9x) = -(45)÷(-9)

x = 5

Since we did all of this to BOTH sides of the equation, both sides are still equal to each other and the equation still is true.

Now apply x = 5 to either of the initial equations to find the value of Y

y = -5x + 24 or y = 4x - 21

(I'll do both but u only need one)

y = -5(5) + 24

y = -25 + 24

y = -1

y = 4(5) - 21

y = 20 - 21

y = -1

Either way, X is 5 and Y is -1

Answer (5, -1)

5 0
3 years ago
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