1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dafna11 [192]
3 years ago
9

What is responsible for support structure and movement in cells

Biology
1 answer:
vekshin13 years ago
5 0
I can help you with that, hfnj2013! :3 The cytoskeleton is responsible for the support structure and movement of cells in your body. Hope that helps!!! XP
You might be interested in
Positive feedback is when the change caused by the stimulus is
sattari [20]

Answer:

A feedback loop

Explanation:because

8 0
3 years ago
Norepinephrine, serotonin, and dopamine are all examples of _______.A. bodily humors. B. synaptic clefts.
Hatshy [7]

The question is incomplete as it does not have the options which are:

A.bodily humors. B.synaptic clefts. C.neurotransmitters. D.growth hormones.

Answer:

The correct answer will be option- C

Explanation:

Neurotransmitters are the chemicals released from the neurons at the synaptic junctions which helps in the transmission of the electrical impulse from one neuron to another.

The dopamine, serotonin and nor-epinephrine are the biogenic forms of neurotransmitters which are synthesized from the precursors of the amino acids. These neurotransmitters are produced in producing different functions in the body.

Thus, option- C is the correct answer.

6 0
3 years ago
Three linked autosomal loci were studied in smurfs.
cupoosta [38]

Answer:

height -------- color --------- mood

           (13.2cM)      (14.5cM)

C=0.421

I = 0.579

Explanation:

We have the number of descendants of each phenotype product of the tri-hybrid cross.

Phenotype Number

  • pink, tall, happy            580
  • blue, dwarf, gloomy     601
  • pink, tall, gloomy         113
  • blue, dwarf, happy      107
  • blue, tall, happy              8
  • pink, dwarf, gloomy        6
  • blue, tall, gloomy          98
  • pink, dwarf, happy      101

Total number of individuals = 1614 = N

Knowing that the genes are linked, we can calculate genetic distances between them. First, we need to know their order in the chromosome, and to do so, we need to compare the phenotypes of the parental with the ones of the double recombinants. We can recognize the parental in the descendants because their phenotypes are the most frequent, while the double recombinants are the less frequent. So:

Parental)

  • Pink, tall, happy            580 individuals
  • Blue, dwarf, gloomy      601 individuals

Simple recombinant)

  • Pink Tall Gloomy           113 individuals
  • Blue, Dwarf, Happy       107 individuals
  • Blue Tall Gloomy             98 individuals
  • Pink Dwarf Happy          101 individuals

Double Recombinant)  

  • Blue Tall Happy                 8 individuals
  • Pink  Dwarf Gloomy           6 individuals  

Comparing them we realize that parental and double recombinant individuals differ in the position of the gene codifying for <u>color</u><u>.</u> They only change in the position of Blue and Pink. This suggests that the position of the color gene is in the middle of the other two genes, height and mood, because in a double recombinant only the central gene changes position in the chromatid.  

So, the alphabetic order of the genes is:

---- height ---- color ----- mood ----

Now we will call Region I to the area between Height and Color, and Region II to the area between Color and Mood.

Once established the order of the genes we can calculate distances between them, and we will do it from the central gene to the genes on each side. First We will calculate the recombination frequencies, and we will do it by region. We will call P1 to the recombination frequency between Height and color genes, and P2 to the recombination frequency between color and mood.

P1 = (R + DR) / N

P2 = (R + DR)/ N

Where: R is the number of recombinants in each region (the ones that have an intermediate phenotypic frequency), DR is the number of double recombinants in each region, and N is the total number of individuals.  So:

Region I

Tall------ Pink--------happy  (Parental) 580 individuals

Dwarf ---Pink------- Happy (Simple Recombinant) 101 individuals

Dwarf--- Pink-------Gloomy (Double Recombinant) 6 individuals

Dwarf----Blue-------Gloomy (Parental) 601 individuals

Tall ------Blue------- Gloomy (Simple Recombinant)  98 individuals

Tall ----- Blue------- Happy   (Double Recombinant) 8 individuals  

Region II

Tall------ Pink--------happy (Parental) 580 individuals

Tall-------Pink------- Gloomy (Simple Recombinant) 113 individuals

Dwarf----Pink------- Gloomy (Double Recombinant) 6 individuals

Dwarf----Blue-------Gloomy (Parental) 601 individuals

Dwarf ----Blue-------Happy (Simple Recombinant) 107 individuals

Tall ----- Blue------- Happy   (Double Recombinant) 8 individuals

In each region, the highlighted traits are the ones that suffered recombination.

  • P1 = (R + DR) / N

P1 = (101+6+98+8)/1614

P1 = 213/1614

P1 = 0.132    

  • P2= = (R + DR) / N

P2 = (113+6+107+8)/1614

P1 = 234/1614

P1 = 0.145

Now, to calculate the recombination frequency between the two extreme genes, height and mood, we can just perform addition or a sum:

  • P1 + P2= Pt

0.132 + 0.145 = Pt

0.277=Pt

The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).  

The map unit is the distance between the pair of genes for which every 100 meiotic products, one results in a recombinant product.  

Now we must multiply each recombination frequency by 100 to get the genetic distance in map units:

GD1= P1 x 100 = 0.132 x 100 = 13.2 MU = 13.2 cM

GD2= P2 x 100 = 0.145 x 100 = 14.5 MU = 14.5 cM

GD3=Pt x 100 = 0.277 x 100 = 27.7 MU = 27.7 cM

To calculate the coefficient of coincidence, CC, we must use the next formula:

CC= observed double recombinant frequency/expected double recombinant frequency

Note:  

-observed double recombinant frequency=total number of observed double recombinant individuals/total number of individuals

-expected double recombinant frequency: recombination frequency in region I x recombination frequency in region II.

  • CC= ((6 + 8)/1614)/0.132x0.145

        CC=0.008/0.019

        CC=0.421

The coefficient of interference, I, is complementary with CC.

I = 1 - CC

I = 1 - 0.421

I = 0.579

8 0
3 years ago
How has selective breeding changed the wolf into the many different breeds of domestic dogs that we know today?
ivanzaharov [21]

D.All of the Above

How has selective breeding changed the wolf into the many different breeds of domestic dogs that we know today?

a. Animals with the traits that were desired were bred to each other.

b. As civilization changed, so did our need and desire for different types of dogs.

c. The fear of humans was bred out of wild wolves.

d. All of the above.

6 0
2 years ago
Read 2 more answers
Does anybody know the answer to this question please help me 10 more minutes
bija089 [108]

Answer:

The answer is number two extinction happened, this was the time dinosaurs went extinct ebcause lack of sun because oh how much dirt was blown into the earth atmosphere becuase of the asteriod, third option is talking about big bang theroy so that dosnt apply!

Explanation:

3 0
3 years ago
Other questions:
  • Rabia is using a relaxation technique in which she systematically contracts and releases different muscle groups. What is the te
    7·1 answer
  • Which of the following statements about the nucleus is true?
    5·2 answers
  • The Venn diagram compares aerobic respiration and anaerobic respiration. Which statement should be categorized only in the aerob
    14·2 answers
  • Explain how the data in the table can be used to determine possible evolutionary relationships.
    15·1 answer
  • How can a map of the seafloor be generated using mechanical waves?<br> Please Help!!!
    7·1 answer
  • Use the principle of original horizontality to identify the two rocks that are nearly the same age.
    11·1 answer
  • Question 5 (1 mark)
    13·1 answer
  • The picture shows a contractile vacuole of a unicellular freshwater organism. The contractile vacuole regulates the flow of wate
    15·1 answer
  • Which characteristic do cows and dogs share?
    7·1 answer
  • List two functions of the skeleton (2)<br><br>​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!