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BigorU [14]
3 years ago
12

What is tge total surface area of a solid sphere of diameter 14cm

Mathematics
1 answer:
Alborosie3 years ago
7 0

The surface area of a sphere of radius r is A = 4π*r^3.


Since the radius in this case is 7 cm (half the 14 cm diameter), the area of this sphere is


A = 4π(7 cm)^2, or 196π cm^2.

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<h3><u>Question:</u></h3>

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units.

The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

<h3><u>Answer:</u></h3>

Dimensions of cylinder A are multiplied by \frac{3}{2}  to produce the corresponding dimensions of cylinder B

<h3><u>Solution:</u></h3>

Cylinders A and B are similar solids.

The base of cylinder A has a circumference of 4 \pi units

The base of cylinder B has an area of 9 \pi units

Let "x" be the required factor

From given question,

Dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B

Therefore, we can say,

\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }

<h3><u>Cylinder A:</u></h3>

The circumference of base of cylinder (circle ) is given as:

C = 2 \pi r

Where "r" is the radius of circle

Given that  base of cylinder A has a circumference of 4 \pi units

Therefore,

4 \pi = 2 \pi r\\\\r = 2

Thus the dimension of cylinder A is radius = 2 units

<h3><u>Cylinder B:</u></h3>

The area of base of cylinder (circle) is given as:

A = \pi r^2

Given that,  the base of cylinder B has an area of 9 \pi units

Therefore,

\pi r^2 = 9 \pi\\\\r^2 = 9\\\\r = 3

Thus the dimension of cylinder B is radius = 3 units

\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }\\\\2 \times x = 3\\\\x = \frac{3}{2}

Thus dimensions of cylinder A are multiplied by \frac{3}{2}  to produce the corresponding dimensions of cylinder B

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