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bogdanovich [222]
3 years ago
15

What is the radius of the circle whose equation is x2 + y2 = 8?

Mathematics
2 answers:
gavmur [86]3 years ago
5 0
If that is x^2+y^2=8
then the radius is 2\sqrt{2}
ikadub [295]3 years ago
5 0

Answer:

The radius of the circle whose equation is x^{2}+y^{2}=8 is 2\sqrt{2}

Step-by-step explanation:

The equation of a circle centered at the origin (0,0) and radius R is :

x^{2}+y^{2}=R^{2} (I)

Where ''R'' is a real number.

For the equation given, we know that

R^{2}=8 ⇒

R=\sqrt{8}

R=\sqrt{(2).(4)}

R=2\sqrt{2}

We found out that the radius of the circle is R=2\sqrt{2}

For another circle, for example centered at the point (a,b) and radius R the equation is :

(x-a)^{2}+(y-b)^{2}=R^{2}  (II)

Notice that if we replace the point (a,b) by (0,0) ⇒

(x-0)^{2}+(y-0)^{2}=R^{2} ⇒

x^{2}+y^{2}=R^{2}

We obtain the equation (I).

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