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3 years ago

Find the value of the underlined digit 9 In 10698

Mathematics

2 answers:

Nookie1986 [14]3 years ago

8 0

Tenths yuuuuuuuuuuuuup

Murljashka [212]3 years ago

5 0

Answer:

In 10698 9 is at tens position

therefore value of 9 in this number is 90

Step-by-step explanation:

in the given number

10698

8 is at ones position

9 -tens

6-hundreds

0-thousands

1-ten thousands

therefore the value of 9 in the number 10698 is 90

You might be interested in

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago

PLEASE HELP NOW! (-2, -4) and (-3, -3) in a linear equation

chubhunter [2.5K]

The linear equation is y = -x - 6

Step-by-step explanation:

To form a linear equation from two points lie on the line which the equation represented it

Find the slope of the line by using the formula $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
Then use the slope-intercept form of the equation y = m x + b
To find the value of b substitute x and y of the equation by the coordinates of one of the two given points

∵ Points (-2 , -4) and (-3 , -3) lie on the line

∴ $x_{1}$ = -2 and $x_{2}$ = -3

∴ $y_{1}$ = -4 and $y_{2}$ = -3

- Substitute these values in the formula of the slope

∵ $m=\frac{-3-(-4)}{-3-(-2)}=\frac{-3+4}{-3+2}=\frac{1}{-1}$

∴ m = -1

∵ The form of the equation is y = m x + b

∵ m = -1

∴ y = (-1) x + b

∴ y = -x + b

To find b substitute x and y in the equation by the coordinates of

point (-2 , -4) OR (-3 , -3)

∵ x = -3 and y = -3

∴ -3 = -(-3) + b

∴ -3 = 3 + b

- Subtract 3 from both sides

∴ -6 = b

∴ The equation is y = -x + (-6)

∴ y = -x - 6

The linear equation is y = -x - 6

Learn more:

You can learn more about linear equation in brainly.com/question/4326955

#LearnwithBrainly

4 0

3 years ago

Solve for x. −5(x−4)=−30

Readme [11.4K]

Let's solve your equation step-by-step.−5(x−4)=−30

Step 1: Simplify both sides of the equation.−5(x−4)=−30
Simplify: (Show steps)−5x+20=−30

Step 2: Subtract 20 from both sides.−5x+20−20=−30−20−5x=−50

Step 3: Divide both sides by -5.−5x−5=−50−5x=10

Answer:x=10

8 0

3 years ago

Read 2 more answers

Please, I really need help with this! What is the volume of the cone?

MariettaO [177]

V=1/3*πr² *h,
raduus r=32/2=16
V=1/3*3.14*(16)² *18=6*3.14*(16)² =4823.04

3 0

3 years ago

I put a picture —PLEASE HELP

Karo-lina-s [1.5K]

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