Answer:

Step-by-step explanation:
<h3>METHOD 1:</h3>

<h3>METHOD 2:</h3>

<u>Answer:</u>
Below!
<u>Step-by step explanation:</u>
<u>We know that:</u>
<u>Solution of Question A:</u>
<u>Percent of children: Total children/Total attendance</u>
- => 400/1500
- => 4/15
- => 0.27 (Rounded to nearest hundredth)
- => 0.27 x 100
- => 27%
<u>Hence, the percent of children is about 27%.</u>
<u>Solution of Question B:</u>
<u>Percent of women: Total women/Total attendance</u>
- => 850/1500
- => 85/150
- => 17/30
- => 17/30 x 100
- => 17/3 x 10
- => 170/3
- => 56.67%
<u>Hence, the percent of women is 56.67%.</u>
<u>Solution of Question C:</u>
- 400 + 850 + m = 1500
- => 1250 + m = 1500
- => m = 1500 - 1250
- => m = 250
<u>Percent of men: Total men/Total attendance</u>
- => 250/1500
- => 1/6
- => 0.17 (Rounded to nearest hundredth)
- => 0.17 x 100
- => 17%
<u>Hence, the percent of men is about 17%</u>
Hoped this helped.

A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
which inequality? where the question ?
Step-by-step explanation: